Orbital Period of satellite in terms of v and r

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SUMMARY

The orbital period T of a satellite in a circular orbit can be derived using the formula T = (2πr) / v, where r is the orbital radius and v is the orbital speed. The discussion emphasizes that the distance for one complete revolution is the circumference of the orbit, which is 2πr. The centripetal acceleration equation is deemed unnecessary for this derivation, as the relationship between distance, speed, and time suffices to compute the period directly.

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  • Understanding of circular motion and orbital mechanics
  • Familiarity with the concepts of speed and distance
  • Basic knowledge of algebra for manipulating equations
  • Knowledge of the relationship between velocity and acceleration
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Homework Statement


"A satellite orbits the Earth in a circular orbit of radius r. If the orbital speed of the satellite is v, what is the orbital period T of the satellite in terms of v and r? You must explain how you derive the expression for the period."

Homework Equations


Speed = distance/time
a = v2/r

The Attempt at a Solution


Distance for 1 revolution of a circle is equal to the circumference. So distance = 2(pi)r
Time to travel 1 revolution = period T

So velocity = speed = 2(pi)r/T

a = v2/r

a = 2(pi)r/T * 1/T

a = 2(pi)r / T2

At this point I would solve for T, but I am not sure if this is valid, what I'm doing? I don't think we are supposed to have an acceleration in there, so I was wondering if there is another equation I could use that relates v and r. Btw this is not graded, it's just a sample test (that we're not turning in) to help us for the real test (on Tuesday). Thanks for any assistance.
 
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I don't think you even need to bother with the centripetal acceleration equation.

If we have an orbital radius of r, this gives an orbital path distance of 2∏r

T = d / v ---> T = (2∏r) / v
 
If you know the distance per revolution, and you know the velocity, surely you can compute the time of one revolution.
 
bossman27 said:
I don't think you even need to bother with the centripetal acceleration equation.

If we have an orbital radius of r, this gives an orbital path distance of 2∏r

T = d / v ---> T = (2∏r) / v

Oh thanks, so I could have stopped there and solved for T. I guess I made it too complicated. So that answers the question right?
 
Cloud 9 said:
Oh thanks, so I could have stopped there and solved for T. I guess I made it too complicated. So that answers the question right?

Yup, in general you want to use the least amount of extra variables/equations possible.
 

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