Organic chemistry acetal reaction help

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
16 replies · 3K views
IntegralDerivative
Messages
27
Reaction score
3
<Moderator's note: Moved from a technical forum and thus no template.>

OChem Question:
o7XLLLJ.jpg
My Answer:

upload_2017-10-2_16-43-9.png


Not sure if this is correct. Anyone?
 

Attachments

  • upload_2017-10-2_16-43-3.png
    upload_2017-10-2_16-43-3.png
    2.6 KB · Views: 630
Last edited by a moderator:
Physics news on Phys.org
What's your reasoning for the cyclohexanol hosting an acetal carbon?

Edit: is this homework? If so, it belongs in the homework forums.
 
  • Like
Likes   Reactions: IntegralDerivative
TeethWhitener said:
What's your reasoning for the cyclohexanol hosting an acetal carbon?

Edit: is this homework? If so, it belongs in the homework forums.

Cyclohexanol is larger. I think it could go either way. Are there major and minor products here? Sorry I thought this was the homework forum. How do I move this thread?
 
I asked the mods to migrate the thread. Meanwhile, can you tell me how to make an acetal? What functional groups are required?
 
  • Like
Likes   Reactions: IntegralDerivative
TeethWhitener said:
I asked the mods to migrate the thread. Meanwhile, can you tell me how to make an acetal? What functional groups are required?

Thank you so much. You need alcohols, a leaving group (like H2O) and acid catalyst to make an acetal.
 
IntegralDerivative said:
Thank you so much. You need alcohols, a leaving group (like H2O) and acid catalyst to make an acetal.
Alcohol and? What other organic functionality do you need?
 
  • Like
Likes   Reactions: IntegralDerivative
TeethWhitener said:
Alcohol and? What other organic functionality do you need?

Carbonyl group?
 
  • Like
Likes   Reactions: TeethWhitener
Yes. If you have a carbonyl group, what happens if you add one equivalent of alcohol? (Formally, ignoring equilibrium considerations) Do you get an acetal right off the bat?
 
  • Like
Likes   Reactions: IntegralDerivative
TeethWhitener said:
Yes. If you have a carbonyl group, what happens if you add one equivalent of alcohol? (Formally, ignoring equilibrium considerations) Do you get an acetal right off the bat?

You will get a hemiacetal. But I thought you need oxidizing agents to turn alcohols into carbonyls? How do we get a carbonyl in this case with only sulfuric acid?
 
  • Like
Likes   Reactions: TeethWhitener
IntegralDerivative said:
You will get a hemiacetal. But I thought you need oxidizing agents to turn alcohols into carbonyls? How do we get a carbonyl in this case with only sulfuric acid?
You're getting ahead of yourself. Look at your original problem and tell me what functionalities you have.
Edit: hemiacetal is right (and is the important part). The rest of the post veers off the path a little.
 
  • Like
Likes   Reactions: IntegralDerivative
TeethWhitener said:
You're getting ahead of yourself. Look at your original problem and tell me what functionalities you have.
Edit: hemiacetal is right (and is the important part). The rest of the post veers off the path a little.

I see. So the hemiacetal is the
upload_2017-10-2_17-44-23.png
. and so it will form a carbonyl after the H2O group leaves and then the cyclohexanol will attack to the carbonyl carbon?

Do you know how to name the
upload_2017-10-2_17-44-23.png
molecule?
 
IntegralDerivative said:
I see. So the hemiacetal is the View attachment 212179 . and so it will form a carbonyl after the H2O group leaves and then the cyclohexanol will attack to the carbonyl carbon?

Do you know how to name the View attachment 212179 molecule?
You've added a step. "Hemiacetal" literally means "half an acetal." Meaning you're already halfway to an acetal. Take another stab at it.
 
  • Like
Likes   Reactions: IntegralDerivative
TeethWhitener said:
You've added a step. "Hemiacetal" literally means "half an acetal." Meaning you're already halfway to an acetal. Take another stab at it.
I am not sure what you mean. I described these steps here I think:

upload_2017-10-2_17-51-52.png
 
IntegralDerivative said:
I am not sure what you mean. I described these steps here I think:

View attachment 212181
Ah I see what you're saying. That's an oxonium, not a carbonyl. Yes, these are the steps you want. So what's your final product?
 
  • Like
Likes   Reactions: IntegralDerivative
TeethWhitener said:
Ah I see what you're saying. That's an oxonium, not a carbonyl. Yes, these are the steps you want. So what's your final product?

This:
upload_2017-10-2_17-59-22.png
 
  • Like
Likes   Reactions: TeethWhitener
TeethWhitener said:
Good work.

Thank you so much!