TeethWhitener said:What's your reasoning for the cyclohexanol hosting an acetal carbon?
Edit: is this homework? If so, it belongs in the homework forums.
TeethWhitener said:I asked the mods to migrate the thread. Meanwhile, can you tell me how to make an acetal? What functional groups are required?
Alcohol and? What other organic functionality do you need?IntegralDerivative said:Thank you so much. You need alcohols, a leaving group (like H2O) and acid catalyst to make an acetal.
TeethWhitener said:Alcohol and? What other organic functionality do you need?
TeethWhitener said:Yes. If you have a carbonyl group, what happens if you add one equivalent of alcohol? (Formally, ignoring equilibrium considerations) Do you get an acetal right off the bat?
You're getting ahead of yourself. Look at your original problem and tell me what functionalities you have.IntegralDerivative said:You will get a hemiacetal. But I thought you need oxidizing agents to turn alcohols into carbonyls? How do we get a carbonyl in this case with only sulfuric acid?
TeethWhitener said:You're getting ahead of yourself. Look at your original problem and tell me what functionalities you have.
Edit: hemiacetal is right (and is the important part). The rest of the post veers off the path a little.
You've added a step. "Hemiacetal" literally means "half an acetal." Meaning you're already halfway to an acetal. Take another stab at it.IntegralDerivative said:I see. So the hemiacetal is the View attachment 212179 . and so it will form a carbonyl after the H2O group leaves and then the cyclohexanol will attack to the carbonyl carbon?
Do you know how to name the View attachment 212179 molecule?
I am not sure what you mean. I described these steps here I think:TeethWhitener said:You've added a step. "Hemiacetal" literally means "half an acetal." Meaning you're already halfway to an acetal. Take another stab at it.
Ah I see what you're saying. That's an oxonium, not a carbonyl. Yes, these are the steps you want. So what's your final product?IntegralDerivative said:
TeethWhitener said:Ah I see what you're saying. That's an oxonium, not a carbonyl. Yes, these are the steps you want. So what's your final product?
IntegralDerivative said:This: View attachment 212182
TeethWhitener said:Good work.