Why Is My Calculated Molar Mass of Phthalic Acid Different from My Peers'?

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Discussion Overview

The discussion revolves around the discrepancy in the calculated molar mass of phthalic acid obtained by a participant compared to their peers. The context is a laboratory experiment involving titration with NaOH to determine the chemical formula and molar mass of the compound.

Discussion Character

  • Homework-related
  • Debate/contested
  • Exploratory

Main Points Raised

  • The participant calculated a molar mass of approximately 135g for phthalic acid, which is about 30 grams lower than the values reported by peers.
  • The participant's professor confirmed that all calculations performed by the participant were correct.
  • One participant suggested that contamination of the chemical sample might explain the discrepancy.
  • Another participant noted that the samples were sourced from the same origin, questioning the contamination hypothesis.
  • There was a request for the participant to show details of their calculations to further investigate the issue.
  • Participants inquired whether the same titrant was used as others and which volume of NaOH was applied for the titration.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the cause of the discrepancy in molar mass calculations. Multiple competing views regarding potential contamination and procedural differences remain unresolved.

Contextual Notes

The discussion does not clarify specific assumptions regarding the experimental setup or the exact procedures followed by the participant and their peers. There is also a lack of detail on the volumes of NaOH used in the titration.

A_lilah
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Homework Statement



We did an experiment in lab today where we were given a compound and we had to figure out the chemical formula and molar mass using titration (titrated with NaOH). The compound I got was phthalic acid, and the average molar mass I got was ~135g. This is about 30 grams off of what everyone else in my group got.

Homework Equations



[(M NaOH)(L NaOH)]/2 = moles of phthalic acid (there were two equivalency points, which is why it had to be divided by 2)

moles phthalic acid / mass of sample used = grams of phthalic acid

We were then given the mass percents of each element, and I divided these by the atomic masses of each element, then used the ratio of them to figure out the chemical formula, and whether it was a multiple of the ratios used or not (it was: actual formula = C6H4O2)

My professor said all of my calculations were correct.

The Attempt at a Solution



So my ultimate question is: Why is my molecular mass 30 grams short of everyone else who used phthalic acid? I did the titration 4 times (the 4th time with the TA watching~ an interesting experience), and all 4 times I got between 130 and 137.

Any ideas would be great. Thanks! :)

(ps~ this may be the wrong place to post this, but I wasn't sure...)
 
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If even your professor has verified all your calculations, then perhaps you can blame a contaminated chemical sample @.@
 
I thought of that too, but the prof said that the samples were all from the same source... good thinking though
 
Show details of your work.

Have you used the same titrant others did?
 
Which volume of NaOH titratant did you use? The one for the first eq. point or the second?
 

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