A student titrated a .4630g of unknown monoprotic acid with .1060M NaOH. The equivalance point volume is 28.70mL. a) Calculate the number of moles of NaOH used. Im pretty sure I got this one I did .1060 M X .02870L to equal 3.04E-3 mol b)how many equivalents of unknown acid were titrated? no clue c) Determine the equivalent mass of the unknown acid Which is the moles times MM There is also a table given of acids and there pKa and equivalent masses. If I can figure out what Pka is I should be fine.