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I Orientation of Earth, Sun and Solar System in the Milky Way

  1. Oct 10, 2016 #1
    I've been tinkering with a few diagrams in an attempt to illustrate the motion of the solar system in its journey around the Milky Way. I also wanted portray how the celestial, ecliptic and galactic coordinate systems are related to each other in a single picture. Note: in the Celestial, or Equatorial system, the Celestial North Pole (an extension of the Earth's axis of rotation), uses the default setting of North as "up." The Ecliptic and Galactic also use North as "up" with reference to the Celestial North Pole. Some people say that in space there is no such thing as "up" or "down," but in determining the position of a celestial object (e.g., declination and right ascension of a star or deep-sky object) is DOES matter.

    Please have a look at these diagrams and feel free to comment on any errors, or make suggestions as to how I could make them better. I drew these images, but anyone is free to re-use them without restriction.

    Figure 1 shows the motion of the Earth and Sun around the Milky Way. The solar system is actually well within the galactic disk, which is about 1,000 light years thick. The sun and the planets that circle it is roughly 50 light years above the galactic plane, and passed northward through it about 3 million years ago in its undulating path around the galactic center. Note: this diagram is not to scale. The northernmost excursion of the solar system takes it about 250 light years above the galactic plane. This means it would only subtend an angle of about 0.55° relative to the galactic center.

    Figure 1. Motion of Earth and Sun around the Milky Way

    Motion of Earth and Sun around Milky Way (ESO_ 10Oct2016.jpg

    Figures 2. and 3. show the orientation of the Earth, Sun & Solar System in the Milky Way - similar diagrams, just presented in different ways.

    Figure 2. Orientation of Celestial, Ecliptic and Galactic Poles and Planes

    There Planes & angles_no earth 09Oct2016.jpg

    Figure 3. Orientation of astronomical coordinates projected on the Celestial Sphere.

    Celestial, Ecliptic & Galatic Poles-Planes - 29Sep2016nojs.jpg


    The angle between Celestial Equator (an imaginary plane passing through the earth's equator) and the Ecliptic Plane (an imaginary plane extended through the Sun's equator) is 23.4°. The angle between the North Celestial Pole (an imaginary line extending through Earth's axis of rotation) and the North Ecliptic Pole (an imaginary line extending through the Sun's axis of rotation) is the same - 23.4°. This is the familiar value for the "tilt" of the Earth in its path around the Sun.

    The angle between the Ecliptic Plane and the Galactic Equator (an imaginary plane passing through, and parallel to, the disk of the Milky Way) is 60.2°. The angle between the North Ecliptic Pole and the North Galactic Pole (an imaginary line extending through the Milky Way's axis of rotation) is also 60.2°.

    The angle between the Celestial Equator and the Galactic Equator is 62.9°, as is the angle between the North Celestial Pole and the North Galactic Pole.

    These three angles = 23.4°, 60.2° and 62.9° cannot be shown or calculated in two dimensions, because they represent separate planes which do not intersect at a common point. If you look at Figure 3, you can see that this is so.

    References:
    https://en.wikipedia.org/wiki/Celestial_coordinate_system#Galactic_system
    https://www.eso.org/public/news/eso0932/
    http://www.engineeringanddesign.com/1/054.htm
     
    Last edited: Oct 10, 2016
  2. jcsd
  3. Oct 12, 2016 #2

    phyzguy

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    Nice! I didn't check the accuracy, but they look reasonable. My only comment is that in the first diagram, I would change "Celestial Plane" to "Celestial Equator" as you have done in the other two diagrams.
     
  4. Oct 12, 2016 #3

    Janus

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    I'd just make one small point. In your first diagram, it appears as if you are showing the Moon's orbit as being on the same plane as the Celestial plane/equator, where, in reality, it is inclined by ~5 degrees to the ecliptic (~18 degrees to the Celestial equator).
     
  5. Oct 12, 2016 #4
    Thanks phyzguy, and appreciated. I called it Celestial Plane to be consistent with the terms Galactic Plane and Ecliptic Plane I used in this diagram. But you're right - it should be referred to as the Celestial Equator - I will adjust accordingly. See image attached to my following reply to Janus.

    Cheers.
     
  6. Oct 12, 2016 #5
    Thanks Janus - I knew the moon's orbit was inclined relative to earth's equator, but I didn't know it was inclined TOWARD the ecliptic. Interesting! I've included your suggestion in my diagram, which also includes phyzguy's suggestion. Really appreciate the input, hope this diagram isn't getting too busy.

    Motion of Earth and Sun around Milky Way (ESO) 12Oct2016.jpg
     
  7. Apr 16, 2017 #6
    quote: I drew these images, but anyone is free to re-use them without restriction.

    Thanks for sharing this great diagram!

    quote: feel free to comment on any errors, or make suggestions as to how I could make them better

    The definition of an ellipse is that it has 2 focus points,
    therefore the the Sun is not at the center of the Earth's elliptical orbit.
    The direction of the "Super Galactic Center"
    would be a perpendicular line to the Earth's orbit, at about October 11.


    seasons.gif
     
    Last edited: Apr 16, 2017
  8. Apr 17, 2017 at 2:48 PM #7
    Thanks for your input. Yes, the Earth's orbit around the Sun is elliptical, but it's very nearly (97%) circular. Earth's apogee distance from the Sun is 152.1 million km, and its perigee distance is 147.1 million km. The orbit is shown to scale in the diagram below. Looks much like a circle, doesn't it?

    The Earth-Sun system orbits a common center of mass called the barycenter. But because the Sun is so much more massive (99.9% of the mass of the entire solar system), the Earth-Sun barycenter is only about 449 km from the center of the Sun.

    Elliptical Orbit of Earth around Sun 17Apr2017s.jpg

    "Super Galactic Center" is not an astronomical term, as far as I know. If you mean the Galactic Center, I still have trouble visualizing what you mean by "a perpendicular line to Earth's orbit." A diagram might help.
     

    Attached Files:

  9. Apr 17, 2017 at 7:35 PM #8
    Looking at the Sun's direction of travel arrow on fizixfan's 'Motion of Earth & Sun around the Milky Way' diagram, does this mean then that the solar system is orbiting the Galaxy in a clockwise direction? Also, which hemisphere of Earth's is (mostly?) facing the direction the solar system is taking during its orbit round the galactic disc? North or South? Or do they each take turns during the course of a terrestrial year? I can't quite put it all together it somehow.
     
  10. Apr 18, 2017 at 12:29 PM #9
    The short answer is yes, it is. In astronomy, there are conventional means for defining the positions and locations of celestial objects. The three most commonly used are the Celestial Coordinate System (with Earth as the primary point of reference), the Ecliptic Coordinate System (with the Sun as the primary point of reference) and the Galactic Coordinate System (Sun at center, with the primary direction aligned with the approximate center of the Milky Way galaxy).

    In all three of this systems, Earth's North Pole is pointing "up" (you have to start somewhere). So in this frame of reference the Earth spins counterclockwise (CCW) on its axis, and orbits around the Sun in a CCW motion. The Sun also spins CCW on its axis. But the Solar System is moving clockwise in its orbit around the Milky Way. A lot of illustrations you'll find on the internet get this last part wrong, and if it's pointed out to them, many of them will say, "It doesn't matter, there is no up or down in space." That's true, but if does matter if you're using any kind of astronomical coordinate system.

    That's an interesting question. If you look at my diagram below, and observe the yellow arrow pointing toward the North Celestial Pole - that is aligned with the Earth's axis of rotation. You'll see that the Earth's northern hemisphere is inclined toward (facing, or "leaning into") its direction of motion around the galactic disk.

    Motion of Earth and Sun around Milky Way (ESO) 12Oct2016.jpg
     
    Last edited: Apr 18, 2017 at 12:39 PM
  11. Apr 19, 2017 at 1:03 PM #10
    Thanks, fizixfan. Speaking as an amateur stargazer, the Earth's orientation with respect to the Milky Way has always been something of a puzzle to me. But no longer!
     
  12. Apr 19, 2017 at 7:41 PM #11

    rbelli1

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    These two points can be the same and we usually call that a circle. Just like a rectangle with length and width equal is often called a square. The more specific figure still satisfies the definition of the more general figure. This does not apply here but may in other examples of orbits.

    BoB
     
  13. Apr 19, 2017 at 8:27 PM #12
    Yes if you are looking at the Milky Way from a point of view above it's North pole.
    If you are viewing from below the South pole, the orbit of the solar system appears to be the opposite direction.
     
  14. Apr 21, 2017 at 6:40 AM #13
    Thanks for the info. Just one other question, though: I've since learnt that the solar system is moving towards a point in the Milky Way presently marked by the 4th magnitude star, Lambda Hercules.* This being so, and to give a better idea about the trajectory of the solar system, at which point in the heavens does the solar system appear to originate from? I assume this point probably lies somewhere in the Southern Hemisphere - if only because the constellation of Hercules is in the Northern Hemisphere, but I have no proof of this. PS. I've tried to find out via Google, but despite my best efforts all I get are responses that have little or no bearing on this question.

    *There are several variations concerning this location, but Lambda Hercules still appears to be leading the pack.

    Note: I've since found out from Wikipedia that the 'solar antapex' is near the star, Zeta Canis Minoris! I could delete this query of mine, but I'll include it on this thread just in case others may wish to know the answer to this admittedly obscure question. Many thanks!
     
    Last edited: Apr 21, 2017 at 6:53 AM
  15. Apr 21, 2017 at 7:23 AM #14

    chasrob

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    Excellent renderings. Figure 3 reminds me of the illustrated The Astronomical Companion by Guy Ottewell.
     
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