- #1

chaotixmonjuish

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Given any curve a that does not pass through the origin has an orientation-preserving reparameterization in the polar form:

a(t) = (r(t)*Cos(V(t)),r(r)*Sin(V(t)))

where r(t)= ||a(t)||

The hint has us reference an older problem. I was wondering if someone could give me a push on how to start proving this.