Origin of the half factor in Euler-Lagrange for geodesics

Alex Petrosyan
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I was wondering where does the 1/2 factor come from in the Euler-Lagrange equation, that is:
[tex] L = \sqrt{g_{\mu \nu} \dot{x}^\mu \dot{x}^\nu}[/tex]

implies that [tex]\partial_\mu L = \pm \frac{1}{2} (\partial_\mu g_{\mu \nu} \dot{x}^\mu \dot{x}^\nu )[/tex]

I'm not sure I entirely understand where it comes from. Intuitively, it might be because taking the partial derivative also is a contraction, but every book I've looked in, simply assumes this is true, and I don't understand how.
 
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Doesn't it comes from the derivative of the square root?
 
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@Vanadium 50 , that would also explain the sign ambiguity.
 

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