Origin of the half factor in Euler-Lagrange for geodesics

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SUMMARY

The discussion centers on the origin of the 1/2 factor in the Euler-Lagrange equation for geodesics, specifically in the context of the Lagrangian defined as L = √(g_{μν} ˙x^μ ˙x^ν). The partial derivative of L with respect to the coordinates leads to the expression ∂_μ L = ±(1/2)(∂_μ g_{μν} ˙x^μ ˙x^ν), which arises from the differentiation of the square root function. The sign ambiguity is attributed to the nature of the square root and its derivative, which involves contraction in the context of the metric tensor.

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  • Understanding of the Euler-Lagrange equation
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  • Basic calculus, particularly differentiation of square root functions
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Alex Petrosyan
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I was wondering where does the 1/2 factor come from in the Euler-Lagrange equation, that is:
<br /> L = \sqrt{g_{\mu \nu} \dot{x}^\mu \dot{x}^\nu}<br />

implies that \partial_\mu L = \pm \frac{1}{2} (\partial_\mu g_{\mu \nu} \dot{x}^\mu \dot{x}^\nu )

I'm not sure I entirely understand where it comes from. Intuitively, it might be because taking the partial derivative also is a contraction, but every book I've looked in, simply assumes this is true, and I don't understand how.
 
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Doesn't it comes from the derivative of the square root?
 
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@Vanadium 50 , that would also explain the sign ambiguity.
 

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