Orthogonal projection onto line L

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SUMMARY

The discussion focuses on the concept of orthogonal projection onto a line L in Euclidean space E, defined as Ol = {(P,Q)| P,Q in E and either P lies on L and P=Q or Q is the foot of the perpendicular to L through P}. It is established that Ol is not a rigid motion due to its failure to satisfy conditions (i) and (ii) of definition 3, as well as condition (iii) of definition 1. Specifically, orthogonal projections do not preserve distances, which is a key characteristic of rigid motions.

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  • Comprehension of mathematical definitions and conditions related to projections
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kuhle3133
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Def1. Let L be a line in E. We define the "orthogonal projection onto L" to be
Ol = {(P,Q)| P,Q in E and either
1.P lies on L and P=Q or
2.Q is the foot of the perpendicular to L through P.

Problem 1. Let L be a line in E. Show that Ol is not a rigid motion because it fails condition (iii) of definition 1 and it fails conditions (i) and (ii) of definition 3

Def.1 part (iii) = If P and Q are elements of F, then the second coordinate of P is not the second coordinant of Q.
Def. 3 part (i) = If P is an element of E, then there is an element of F having P as its second coordinant
Def. 3 part (ii) = If (P,P') and (Q,Q') are two elements of F then the segment PQ and P'Q' are congruent.




Homework Equations





The Attempt at a Solution


I can prove that it fails Def 3 part ii because rigid motions preserve distances where orthogonal projections don't, but could use help on the other two.
Thanks
 
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kuhle3133 said:


Def1. Let L be a line in E. We define the "orthogonal projection onto L" to be
Ol = {(P,Q)| P,Q in E and either
1.P lies on L and P=Q or
2.Q is the foot of the perpendicular to L through P.

This is not very well phrased. I think that you mean you are given P and Q is its orthogonal projection onto L.

Problem 1. Let L be a line in E. Show that Ol is not a rigid motion because it fails condition (iii) of definition 1 and it fails conditions (i) and (ii) of definition 3

Def.1 part (iii) = If P and Q are elements of F, then the second coordinate of P is not the second coordinant of Q.[/quote]
You say above that "L is a line in E" which I take to be a Euclidean space, but what is F?
In any case, if P lies on L, the P= Q in which case the second coordinate of P is the second coordinate of Q. Or is there something about F you haven't told us that prohibits this?

Def. 3 part (i) = If P is an element of E, then there is an element of F having P as its second coordinant
Def. 3 part (ii) = If (P,P') and (Q,Q') are two elements of F then the segment PQ and P'Q' are congruent.




Homework Equations





The Attempt at a Solution


I can prove that it fails Def 3 part ii because rigid motions preserve distances where orthogonal projections don't, but could use help on the other two.
Thanks
 

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