Orthogonality and find coefficients

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SUMMARY

The discussion focuses on finding the coefficients c(m) in the general solution of the function f(ρ,t) = Σc(m)Jo(αρ/a) exp[-Dtm²]. The orthogonality relation provided is integral-based, specifically ∫dx x Jo(α(m)x/a)Jo(α(q)x/a) = 0.5a² J1(α)δ(mq), where the integration runs from 0 to a. A key insight is that the exponential term exp[-Dtm²] can be treated as a constant during integration since it does not depend on the integration variable x. This allows for the application of the sifting property in the integration process.

PREREQUISITES
  • Understanding of Bessel functions, specifically Jo(α)
  • Familiarity with orthogonality relations in mathematical physics
  • Knowledge of integral calculus and the sifting property
  • Basic concepts of exponential functions in mathematical expressions
NEXT STEPS
  • Study the properties of Bessel functions and their applications in physics
  • Explore the concept of orthogonality in function spaces
  • Learn about the sifting property in integrals and its implications
  • Investigate the role of exponential decay in differential equations
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Students and researchers in mathematical physics, particularly those working with Bessel functions and orthogonal functions in solving differential equations.

captainjack2000
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Homework Statement


I have that the general solution of a function is
f(\rho,t)=\Sigmac(m)Jo(\alpha\rho\a) exp[-Dtm^2]
where c(m) are constants.
I need to find an expression for c(m) in terms of an integral

Homework Equations


Orthogonality relation given is
\intdx x Jo(\alpha(m)*x/a)Jo(\alpha(q)*x/a = 0.5a^2 J1(\alpha)\delta(mq) where the integral runs between 0 and a and the subscripts on alphas are m and q respectively.

The Attempt at a Solution


I know that you can multiply both sides of the first equation by Jo(\alpha*x/a *x and integrate both sides over the range, using the sifting property given but what happens to the exponential term from the original equation?

 
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captainjack2000 said:

The Attempt at a Solution


I know that you can multiply both sides of the first equation by Jo(\alpha*x/a *x and integrate both sides over the range, using the sifting property given but what happens to the exponential term from the original equation?

The exponential term is independent of your integration variable, x and therefor is constant and it comes outside your integral.
 

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