Oscillations in a magnetic field

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A long bar magnet suspended as a compass needle will oscillate in a magnetic field when displaced from its equilibrium position. The frequency of oscillation is given by the formula f = (1/2pi)*sqrt(μB/I), where μ is the magnetic moment, B is the magnetic field strength, and I is the moment of inertia. The discussion highlights the need to identify the restoring force that brings the needle back to equilibrium. Participants are encouraged to relate this scenario to the harmonic oscillator model, drawing parallels between the equations for spring oscillation and magnetic oscillation. Understanding the transition from the spring constant to the magnetic parameters is crucial for solving the problem.
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Homework Statement


A long, narrow bar magnet that has magnetic moment \vec{\mu} parallel to its long axis is suspended at its center as a frictionless compass needle. When placed in a region with a horizontal magnetic field \vec{B}, the needle lines up with the field. If it is displaced by a small angle theta, show that the needle will oscillate about its equilibrium position with frequency f= (1/2pi)*sqrt(uB/I), where I is the moment of inertia of the needle about the point of suspension.


Homework Equations


No specific equations


The Attempt at a Solution


I remember from my mechanics physics class that I need to figure out what the restoring force is. However, that is where I run into my first problem. I do not know how to model an equation to show how the magnetic field will restore the magnet to equilibrium.
 
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This equation looks the exact same as the equation for the oscillation frequency of a spring f=(1/2pi)*sqrt(k/m). I know it is a harmonic oscillator, but can anyone get me started on how to change from sqrt(k/m) to sqrt(uB/I). Any help on how to start would be greatly appreciated.
 
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Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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