Pair of lines: \determine point of intersection. Please tell me if I am correct.

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Homework Help Overview

The discussion revolves around determining the point of intersection for a pair of linear equations: 3x - 7y = 8 and 2x + 4y = -12. The original poster outlines their steps in solving for the intersection point and seeks validation of their approach.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to solve the equations by substituting one equation into the other and expresses uncertainty about the correctness of their steps. Participants discuss the validity of the steps taken and suggest checking the solution by substituting back into the original equations.

Discussion Status

Participants have provided feedback on the original poster's steps, affirming that the point found satisfies both equations. There is an ongoing exploration of the correctness of the steps taken, with some participants encouraging verification through substitution.

Contextual Notes

The original poster is focused on ensuring that their methodology aligns with proper problem-solving techniques in algebra, indicating a desire for thorough understanding rather than just obtaining the correct answer.

nukeman
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Homework Statement



Ok, I think i got it, but can you all tell me if these are the right/proper steps I must do?

Determine the point of intersection of the following pair of lines:

3x - 7y = 8
2x + 4y = -12

Now, first step is the use the 2nd equation and turn the 2nd equation into:

2x = -12 - 4y
x = -6 - 2y

THEN...subsitute the above date into the 1st equation)

3(-6 - 2y) - 7y = 8

turns into

-18 - 6y - 7y = 8 (just 3 x - 6 and 3 x -2y)

****now I go -6 + -7 = -13y and -18 - 8 = 26

so that then turns into:

-13y = 26

then

y = -2

Correct so far?

NOw for x, we go x = -6-2 (-2) = -2?

so x and y are both -2?

Are those the right steps? is there a better way? Am i correct?




Homework Equations





The Attempt at a Solution

 
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if you ever want to check just plug x=-2 and y=-2 into your original equations
 
Yes right, but are the steps I did correct?
 
Does the point (-2, -2) satisfy both equations; i.e., make both equations true statements? If so, that means that this point is on both lines.

If you have found a point that is on both lines, then it's very unlikely that your steps are wrong.

BTW, your abilities have improved a lot in the last couple of weeks!
 
Mark44 said:
Does the point (-2, -2) satisfy both equations; i.e., make both equations true statements? If so, that means that this point is on both lines.

If you have found a point that is on both lines, then it's very unlikely that your steps are wrong.

BTW, your abilities have improved a lot in the last couple of weeks!

Right. ye the both satisfy both equations.

Are the steps I did to solve t his correct? I know I got the right answer, but I want to make sure I am doing the steps 100% correct
 
Yes, your work is correct. The point I'm making is that many times you can tell whether your work is correct by checking it. In this case, since x = -2 and y = -2 satisfy both equation, the point (-2, -2) is on both lines, and you have verified that the point you found is on both lines.

In that sense, algebra and other mathematics courses are different from, say, and English class, where you have to rely on an expert's judgment to determine whether what you have done is right. In mathematics you can be your own expert just by checking the result you found.
 

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