Paradox found in my first relativity sheet

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
Toby_phys
Messages
26
Reaction score
0
We have got some SR work to do, however we have only had 1 introductory lecture. I have a problem with one of the problems.

Question: A rod of 1m parrallel to the x-axis, travels at un-relativistic speeds at 45 degrees. It passes through a slit - also parallel to the x-axis - that is 1.1 meters wide.

Now assume the rod travels at 0.8c, does it fit through, look at it from both viewpoints, the rod and the slit?

In short, my answer was: I only need to look at the x velocity, y velocity will not cause the slit to shrink. X vlecocity = 0.8cos45 c

If you look at it from the slit's frame, the rod shrinks to about 0.8m and still fits. However if you look at it from the rod's frame, the slit shrinks to 0.9m, the rod doesn't fit.

How is this paradox resolved?
 
on Phys.org
Toby_phys said:
We have got some SR work to do, however we have only had 1 introductory lecture. I have a problem with one of the problems.

Question: A rod of 1m parrallel to the x-axis, travels at un-relativistic speeds at 45 degrees. It passes through a slit - also parallel to the x-axis - that is 1.1 meters wide.

Now assume the rod travels at 0.8c, does it fit through, look at it from both viewpoints, the rod and the slit?

In short, my answer was: I only need to look at the x velocity, y velocity will not cause the slit to shrink. X vlecocity = 0.8cos45 c

If you look at it from the slit's frame, the rod shrinks to about 0.8m and still fits. However if you look at it from the rod's frame, the slit shrinks to 0.9m, the rod doesn't fit.

How is this paradox resolved?
No. in the rod's rest-frame the slit does NOT shrink; it is perpendicular to the direction of motion, so is not affected.
 
Capture.png


Here is a diagram. How is the slit perpendicular to the motion