Paramagnetic system: computing number of microstates

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SUMMARY

The discussion focuses on calculating the number of microstates in a paramagnetic system consisting of N distinguishable particles with 1/2 spin. The total energy of the system is defined as ε(s) = -μH ∑(k=1 to N) s_k, where μ is the magnetic moment and H is the applied magnetic field. Key tasks include finding the number of microstates Ω(E) using combinatorial analysis and Stirling's approximation, determining β = 1/kT for a given energy E, and deriving the final magnetization at equilibrium for two systems in contact. The final magnetization is expressed as m = (N_1m_1 + N_2m_2)/(N_1 + N_2).

PREREQUISITES
  • Understanding of paramagnetic systems and spin statistics
  • Familiarity with combinatorial analysis and Stirling's approximation
  • Knowledge of thermodynamic relations, particularly entropy and temperature
  • Basic concepts of magnetic moment and magnetic fields
NEXT STEPS
  • Study the derivation of the Stirling approximation in statistical mechanics
  • Learn about the relationship between entropy and microstates in thermodynamics
  • Explore the concept of thermal equilibrium in statistical physics
  • Investigate the implications of magnetization in paramagnetic materials
USEFUL FOR

Students and researchers in physics, particularly those focusing on statistical mechanics, thermodynamics, and magnetic systems. This discussion is beneficial for anyone looking to deepen their understanding of paramagnetic systems and microstate calculations.

mondeo2015
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Homework Statement


We are given a paramagnetic system of N distinguishable particles with 1/2 spin where we use N variables
s_k each binary with possible values of ±1 where the total energy of the system is known as:
\epsilon(s) = -\mu H \sum_{k=1}^{N} s_k where \mu is the magnetic moment of the spin and H is the applied magnetic field. We are requested to assume that N is greatly larger than 1 and we are reminded of the definition of arctanh(x) = \frac{1}{2} ln(\frac{1+x}{1-x}). We have the following three parts:
1. We are asked to find the number of microstates for a given energy E \Omega(E) with as many justifiable simplifications as possible.
2. We are asked find \beta = \frac{1}{kT} for a given E and we are asked to use this information to find single-spin magnetization of the system defined as m= \frac{1}{N}\sum_{k=1}^{N} s_k in terms of \beta and H the applied magnetic field. We are advised that m can be treated as a continuous variable where needed.
3. We are told that two systems (N_1,H),(N_2,H) are Temperaturs \beta_1 , \beta_2 and initial magnetizations m_1,m_2 respectively, are brought into contact where only heat can be exchanged and we are asked to use the preceding parts to show that the finial magnetization at equilibrium is given by m = \frac{N_1m_1 + N_2m_2}{N_1+N_2}, noticing the magnetic field is the same for both systems.

Homework Equations


The Stirling approximation N! \approx Nln(N)-N as seen in Wikipedia
https://en.wikipedia.org/wiki/Stirling's_approximation

The Attempt at a Solution


I was thinking for part A the idea is to use the fact that it is the total number of N distinct solutions to an integer equation where the sum of the s' must be some integer m so this is basic combinatorics where it is finding the number of +1 valued s' (denoted l) which determines the sum which is l-(N-l) = 2l-N this is equal to m therefore l must satisfy l = (N+m)/2 so the total number of possibilities is N \choose \frac{N+m}{2} then to get rid of factorials we probably should use the assumption that N is much greater than 1 so a form of Stirling's approximation must be valid and is to be used to simplify it. For part b. I must admit I am stumped as to how to relate this to temperature and for part c I have no clue all I think must happen is thermal equilibrium but how do we reach this nice expression given? This is where I am stuck and need help, I thank all helpers.
 
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To find the number of microstates of N distinguishable objects with spin up or spin down you need to divide the N spins into two smaller groups of nu and nd. There are N distinguishable states so N! possible arrangements, but there are nu indistinguishable states so there are nu! arrangements of these. By simple combinatory analysis the total number of microstates is,
Ω = N!/ (nu!(N- nu)!).
The total energy is E = nu(-μH) + nd(μH) and from this,
nu = (1/2)(N-E/(μH)) = (N/2)(1-E/(NμH))
nd = N - (1/2)(N-E/(μH)) = (N/2)(1+E/(NμH))
In order to find β and magnetization I suggest you use the basic thermodynamical relations:
(∂S/∂E)H,N = 1/T and (∂S/∂H)E,N = m/T where the entropy is S = kBln(Ω)
 

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