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Paramagnetic system: computing number of microstates

  1. Apr 16, 2016 #1
    1. The problem statement, all variables and given/known data
    We are given a paramagnetic system of N distinguishable particles with 1/2 spin where we use N variables
    s_k each binary with possible values of ±1 where the total energy of the sytem is known as:
    [tex] \epsilon(s) = -\mu H \sum_{k=1}^{N} s_k [/tex] where [tex] \mu [/tex] is the magnetic moment of the spin and H is the applied magnetic field. We are requested to assume that N is greatly larger than 1 and we are reminded of the definition of [tex] arctanh(x) = \frac{1}{2} ln(\frac{1+x}{1-x}) [/tex]. We have the following three parts:
    1. We are asked to find the number of microstates for a given energy E [tex]\Omega(E)[/tex] with as many justifiable simplifications as possible.
    2. We are asked find [tex] \beta = \frac{1}{kT} [/tex] for a given E and we are asked to use this information to find single-spin magnetization of the system defined as [tex] m= \frac{1}{N}\sum_{k=1}^{N} s_k [/tex] in terms of [tex] \beta [/tex] and H the applied magnetic field. We are advised that m can be treated as a continuous variable where needed.
    3. We are told that two systems [tex](N_1,H),(N_2,H)[/tex] are Temperaturs [tex] \beta_1 , \beta_2 [/tex] and initial magnetizations [tex] m_1,m_2 [/tex] respectively, are brought into contact where only heat can be exchanged and we are asked to use the preceding parts to show that the finial magnetization at equilibrium is given by [tex] m = \frac{N_1m_1 + N_2m_2}{N_1+N_2} [/tex], noticing the magnetic field is the same for both systems.

    2. Relevant equations
    The Stirling approximation [tex] N! \approx Nln(N)-N [/tex] as seen in Wikipedia

    3. The attempt at a solution
    I was thinking for part A the idea is to use the fact that it is the total number of N distinct solutions to an integer equation where the sum of the s' must be some integer m so this is basic combinatorics where it is finding the number of +1 valued s' (denoted l) which determines the sum which is l-(N-l) = 2l-N this is equal to m therefore l must satisfy l = (N+m)/2 so the total number of possibilities is [tex] N \choose \frac{N+m}{2} [/tex] then to get rid of factorials we probably should use the assumption that N is much greater than 1 so a form of Stirling's approximation must be valid and is to be used to simplify it. For part b. I must admit I am stumped as to how to relate this to temperature and for part c I have no clue all I think must happen is thermal equilibrium but how do we reach this nice expression given? This is where I am stuck and need help, I thank all helpers.
    Last edited: Apr 16, 2016
  2. jcsd
  3. Apr 18, 2016 #2
    To find the number of microstates of N distinguishable objects with spin up or spin down you need to divide the N spins into two smaller groups of nu and nd. There are N distinguishable states so N! possible arrangements, but there are nu indistinguishable states so there are nu! arrangements of these. By simple combinatory analysis the total number of microstates is,
    Ω = N!/ (nu!(N- nu)!).
    The total energy is E = nu(-μH) + nd(μH) and from this,
    nu = (1/2)(N-E/(μH)) = (N/2)(1-E/(NμH))
    nd = N - (1/2)(N-E/(μH)) = (N/2)(1+E/(NμH))
    In order to find β and magnetization I suggest you use the basic thermodynamical relations:
    (∂S/∂E)H,N = 1/T and (∂S/∂H)E,N = m/T where the entropy is S = kBln(Ω)
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