Parametric equations for the tangent line

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SUMMARY

The discussion focuses on finding the parametric equations for the tangent line at the point (cos(-4pi/6), sin(-4pi/6), -4pi/6) on the curve defined by x = cos(t), y = sin(t), and z = t. The correct derivative at the tangent point is r'(-4pi/6) = <-sin(-4pi/6), cos(-4pi/6), 1>, which leads to the equations x = cos(-4pi/6) + (-sin(-4pi/6))t, y = sin(-4pi/6) + cos(-4pi/6)t, and z = -4pi/6 + t. The initial error was using t=0 instead of the specific tangent point.

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Find parametric equations for the tangent line at the point (cos(-4pi/6),sin(-4pi/6),-4pi/6) on the curve x=cost, y=sint,z=t

x(t) = _________
y(t) = _________
z(t) = _________

r'(t) = <-sin(t), cos(t), 1>
r'(0) = <0,1,1>



my answer:
x = cos(-4pi/6) + 0t
y = sin(-4pi/6) +1t
z = -4pi/6 +t

the only part i got correct is the z, anyone know what I am doing wrong?
 
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You want the derivative at the tangent point, not t=0.
 
yea your right, i don't know what i was thinking, thanks
 

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