# Parametrics tangent line with point given

1. Dec 5, 2014

### LBK

1. The problem statement, all variables and given/known data
I understand the setup for finding the slope, but always get confused whether I've fully simplified when trig identities get involved.

2. Relevant equations
My dy/dx is

4sin(θ)cos(θ)
-2csc2(θ) which I simplified to just (-2sin(θ)cos(θ))/(csc2(θ)

Does that simpify to anything better than the way I have done it?

3. The attempt at a solution
Once I simplify the above expression fully, I know how to plug in the point to find the equation. Thanks so much!

2. Dec 5, 2014

### LCKurtz

$-2\sin^3\theta \cos\theta$