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Parametrics tangent line with point given

  1. Dec 5, 2014 #1

    LBK

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    1. The problem statement, all variables and given/known data
    I understand the setup for finding the slope, but always get confused whether I've fully simplified when trig identities get involved.


    2. Relevant equations
    My dy/dx is

    4sin(θ)cos(θ)
    -2csc2(θ) which I simplified to just (-2sin(θ)cos(θ))/(csc2(θ)

    Does that simpify to anything better than the way I have done it?


    3. The attempt at a solution
    Once I simplify the above expression fully, I know how to plug in the point to find the equation. Thanks so much!
     
  2. jcsd
  3. Dec 5, 2014 #2

    LCKurtz

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    Science Advisor
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    ##-2\sin^3\theta \cos\theta##
     
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