- #1

- 453

- 8

## Homework Statement

in title

## Homework Equations

x=2cotθ

y=2sin

dy/dx = 2sin

y-y

point = (-2/√3,(3/2)

y=2sin

^{2}θdy/dx = 2sin

^{3}θcosθy-y

_{1}=m(x-x_{1})point = (-2/√3,(3/2)

## The Attempt at a Solution

Have been stuck for hours

I solved for the dy/dx above, now I need to figure out how to get rid of the θ to get my equation in terms of x

so I was thinking sqrt(y/2) = sinθ and (x/2)*sinθ = cosθ

is this a correct approach?