Parametrizing a Closed Curve in \mathbb{R}^3

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The discussion centers on the parametrization of a closed curve in \mathbb{R}^3, specifically exploring the use of Fourier series for this purpose. The participants emphasize the necessity of ensuring that the curve does not intersect itself while satisfying the boundary condition r(0) = r(1). The conversation highlights that a function can be expressed as a Fourier series if it meets certain criteria, particularly periodicity, which is essential for the problem at hand.

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  • Understanding of closed curves in \mathbb{R}^3
  • Knowledge of Fourier series and their properties
  • Familiarity with boundary conditions in mathematical functions
  • Basic concepts of parametrization in vector calculus
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  • Study the properties of Fourier series and their applications in curve parametrization
  • Explore the mathematical definition and examples of closed curves in \mathbb{R}^3
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Mathematicians, physicists, and engineers interested in curve parametrization, particularly those working with Fourier series and boundary conditions in three-dimensional space.

Dox
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Hello.

In a certain problem I'm interested on, I need to write a general form of the parametrization of a closed curve on \mathbb{R}^3.

I thought in parametrize it using a kind of Fourier series. Could it be possible?

Thing become even worse 'cause I'd like to the curve doesn't cross itself.

Every idea is welcome.

Best wishes.
 
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Would it not be sufficient to say that such a curve is a function r(t)=(x(t),y(t),z(t)), t\in [0,1] such that r(t1)=r(t2) iff r1=0, r2=1.
 
quasar987 said:
Would it not be sufficient to say that such a curve is a function r(t)=(x(t),y(t),z(t)), t\in [0,1] such that r(t1)=r(t2) iff r1=0, r2=1.

Thanks for your answer Quasar987, but that exactly the point. In order to satisfy the boundary condition I must expand in Fourier series, Isn't it?

Thank you very much.
 
I don't know what you mean.

Why do you consider the answer I wrote incomplete/inadequate?
 
I mean:

The condition is r(0)=r(1).

In general a function satisfying that condition could be expand as a Fourier series, Isn't it? Because sine and cosine are periodic functions.
 
If the function is not too wild, yes. But again, what does this have to do with the problem? :confused:
 

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