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A∂^2f(x)/∂x^2 = ∂^2f(-x)/∂(-x)^2 = ∂^2f(-x)/∂x^2 = ∂^2Af(x)/∂x^2

But that looks to be abuse of notation..

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- Thread starter aaaa202
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In summary, the parity operator is a mathematical operator that represents symmetry under inversion in a physical system. It commutes with the second derivative, meaning the order in which they are performed does not affect the outcome. This is significant in quantum mechanics and can simplify calculations for systems with symmetry, such as the quantum harmonic oscillator. However, there are cases where the parity operator and the second derivative do not commute, particularly in systems with an asymmetric potential energy function.

- #1

- 1,169

- 2

A∂^2f(x)/∂x^2 = ∂^2f(-x)/∂(-x)^2 = ∂^2f(-x)/∂x^2 = ∂^2Af(x)/∂x^2

But that looks to be abuse of notation..

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You can do both differentiations separately, then it does not look so bad any more.

A parity operator is a mathematical operator that represents the symmetry of a physical system under inversion. It reverses the sign of all spatial coordinates, essentially flipping the system inside out.

In mathematical terms, the statement "the parity operator commutes with the second derivative" means that the order in which these two operations are performed does not affect the outcome. In other words, applying the parity operator before or after taking the second derivative will give the same result.

This commutation property is important in quantum mechanics, as it allows for certain mathematical simplifications and helps to solve problems related to symmetrical systems. It also plays a role in understanding the behavior of particles with spin.

One example is the quantum harmonic oscillator, where the potential energy function is symmetric with respect to the origin. In this case, the parity operator and the second derivative of the wave function commute, making calculations easier.

Yes, there are certain physical systems where the parity operator and the second derivative do not commute, such as those with an asymmetric potential energy function. In these cases, the commutation property may still hold in certain limited scenarios, but it cannot be applied in a general sense.

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