Partial derivatives - textbook error?

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The discussion centers on a potential error in a textbook regarding the calculation of a partial derivative. Participants clarify that when taking the partial derivative with respect to x, the y variable remains constant, leading to confusion about why certain terms vanish. The Chain Rule is highlighted as a critical concept in understanding the differentiation process, particularly in the context of functions involving products. One participant initially misidentifies the rule applied but later acknowledges the correct application of the Chain Rule. Overall, the conversation emphasizes the importance of understanding differentiation rules in calculus.
JFonseka
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Now in my textbook it shows the following partial derivative solution:

\frac{d}{dx}(3y^{4} + e^{x} sin y) = e^{x} sin y

I thought since it's meant to be the partial derivative in terms of x that the y variable would be untouched.

What's happening?
 
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What's the first derivative of f(x) = 3*(5^4) + e^x * sin(5)?
 
uman said:
What's the first derivative of f(x) = 3*(5^4) + e^x * sin(5)?

e^x ?
 
Try again.
 
uman said:
Try again.

Huh? What else can it be, the rest are all constants.
 
If a constant is multiplied to f(x), it doesn't become 1 after differentiating them both.
 
Hi JFonseka! :smile:
JFonseka said:
What's happening?

The Chain Rule is happening!

d/dx(exsiny) = (d/dx(ex)) siny + ex(d/dx(siny)) :smile:
 
tiny-tim said:
Hi JFonseka! :smile:


The Chain Rule is happening!

d/dx(exsiny) = (d/dx(ex)) siny + ex(d/dx(siny)) :smile:

I get that bit lol, but I don't get why 3y^4 disappeared,
 
Nvm I get it now.
 
  • #10
Thanks to all who helped
 
  • #11
tiny-tim said:
Hi JFonseka! :smile:


The Chain Rule is happening!

d/dx(exsiny) = (d/dx(ex)) siny + ex(d/dx(siny)) :smile:

I think you mean the product rule?
 
  • #12
:redface: oops! :redface:
 
  • #13
:wink:
 

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