Partial differentiation & complex analysis

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Homework Statement


Let Δf= d^2f/dx^2+ d^g/dy^2 (laplace equation - Partial Derivatives) Show Δ(f(g(z))= Mod(g'(z))^2 * Δf(w,v) where g(z)=w(x,y)+v(x,y)i


Homework Equations


we propably need to use cauchy riemman equations: dw/dx = dv/dy and dw/dy = - dv/dx
and chain rule


The Attempt at a Solution


∆f(g(x,y)) = d^2 f/dw^2*((dw/dx)^2 + (dw/dy)^2) + d^2f/dv^2*((dv/dx)^2 + (dv/dy)^2) + 2*d^2f/dwdv*(dw/dx dv/dx + dw/dy dv/dy) + df/dw*(d^2w/dx^2 + d^2w/dy^2) + df/dv*(d^2v/dx^2 + d^2 v/dy^2).

If you use the C-R equations this reduces to the identity you stated

Someone gave me this solution but i can't understand where the term 2*d^2f/dwdv*(dw/dx dv/dx + dw/dy dv/dy) came from?
 
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What's Mod ?

marlon
 
mod is the absolute value
ie lg'(z)l
 
Hi

The term you cannot understand how to get does not contribute anything to the proof and with the CR equations it quals zero.

P.s are you a UCL maths student?