Partial Differentiation (very simple mistake, I think)

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SUMMARY

The discussion centers on the application of partial differentiation, specifically the differentiation of a multivariate function with respect to variables y and x. The user attempts to differentiate the function rearranged as y = z³/3 + xz, but encounters an error in calculating dy/dz and subsequently dy/dx. The correct approach involves applying the chain rule, acknowledging that z is a function of both x and y, which is crucial for accurate differentiation.

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  • Understanding of partial differentiation
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henryc09
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Homework Statement


[PLAIN]http://img408.imageshack.us/img408/7163/partialdifferent.jpg

So this means differentiate w.r.t y first, so I want dz/dy, and then w.r.t x right?

so I rearrange so that y=z3/3 + xz
and differentiate w.r.t z to get dy/dz, and then do 1 over this which i get as:

1/(z2+x)

and then differentiating this w.r.t x, I get
-1/(z2+x)2

which isn't quite right. Can anyone see where I've gone wrong? Thanks.
 
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You need to use the chain rule. Don't forget z still varies with x.
 
vela said:
You need to use the chain rule. Don't forget z still varies with x.

It may help to rewrite z as z(x,y) -- looks clunkier, but I find that it helps me remember that I have multivariate function.
 

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