Partial Fraction Decomposition for ∫18/((x2+9)(x-3))

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Homework Statement



Find ∫18/((x2+9)(x-3))



Homework Equations





The Attempt at a Solution



Im a little stuck on this.

18∫1/((x2+9)(x-3))

Im not sure how to turn this into a partial fraction.. help.

Thanks
 
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charmedbeauty said:

Homework Statement



Find ∫18/((x2+9)(x-3))



Homework Equations





The Attempt at a Solution



Im a little stuck on this.

18∫1/((x2+9)(x-3))

Im not sure how to turn this into a partial fraction.. help.

Thanks

The general form for the PF decomposition would be:

[tex]\frac { 18 }{ (x^{ 2 }+9)(x-3) } =\frac { Ax+B }{ x^{ 2 }+9 } +\frac { C }{ x-3 }[/tex]

First find C by using the Heaviside coverup rule (put x = 3 after multiplying both sides by (x-3).

Then just subtract the [itex]\frac { C }{ x-3 }[/itex] from the LHS and simplify to find the remaining term.
 
Curious3141 said:
The general form for the PF decomposition would be:

[tex]\frac { 18 }{ (x^{ 2 }+9)(x-3) } =\frac { Ax+B }{ x^{ 2 }+9 } +\frac { C }{ x-3 }[/tex]

First find C by using the Heaviside coverup rule (put x = 3 after multiplying both sides by (x-3).

Then just subtract the [itex]\frac { C }{ x-3 }[/itex] from the LHS and simplify to find the remaining term.

ok yeah I figured it out thanks.