1. The problem statement, all variables and given/known data ∫(2x3-4x-8)/(x2-x)(x2+4) dx 2. Relevant equations 3. The attempt at a solution ∫(2x3-4x-8)/x(x-1)(x2+4) dx Next I left off the integral sign so I could do the partial fractions: 2x3-4x-8=(A/x)+(B/(x-1))+((Cx+D)/(x2+4)) 2x3-4x-8=A(x3-x2+4x-4)+B(x3+4x)+(Cx+D)(x2-x) 2x3-4x-8=x3(A+B+C)-x2(A+C-D)+x(4A+4B-D)-4A 2=A+B+C 0=A+C-D -4=4A+4B-D -8=-A(4) A=2 Did I set this up correctly? I'm not entirely sure how to solve for these variables.