- #1

- 365

- 2

## Homework Statement

∫(2x

^{3}-4x-8)/(x

^{2}-x)(x

^{2}+4) dx

## Homework Equations

## The Attempt at a Solution

∫(2x

^{3}-4x-8)/x(x-1)(x

^{2}+4) dx

Next I left off the integral sign so I could do the partial fractions:

2x

^{3}-4x-8=(A/x)+(B/(x-1))+((Cx+D)/(x

^{2}+4))

2x

^{3}-4x-8=A(x

^{3}-x

^{2}+4x-4)+B(x

^{3}+4x)+(Cx+D)(x

^{2}-x)

2x

^{3}-4x-8=x

^{3}(A+B+C)-x

^{2}(A+C-D)+x(4A+4B-D)-4A

2=A+B+C

0=A+C-D

-4=4A+4B-D

-8=-A(4)

A=2

Did I set this up correctly? I'm not entirely sure how to solve for these variables.