Partial Fraction Decomposition for ∫18/((x2+9)(x-3))

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Homework Help Overview

The discussion revolves around the integral ∫18/((x²+9)(x-3)), specifically focusing on the method of partial fraction decomposition to simplify the expression for integration.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial setup for partial fraction decomposition and express uncertainty about how to proceed with the method. There are references to using specific rules, such as the Heaviside cover-up rule, to find coefficients in the decomposition.

Discussion Status

The conversation includes attempts to clarify the process of partial fraction decomposition, with some participants offering guidance on finding coefficients. There is an indication that one participant has resolved their confusion, but no consensus on the overall approach has been reached.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the amount of direct assistance they can provide to one another.

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Homework Statement



Find ∫18/((x2+9)(x-3))



Homework Equations





The Attempt at a Solution



Im a little stuck on this.

18∫1/((x2+9)(x-3))

Im not sure how to turn this into a partial fraction.. help.

Thanks
 
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charmedbeauty said:

Homework Statement



Find ∫18/((x2+9)(x-3))



Homework Equations





The Attempt at a Solution



Im a little stuck on this.

18∫1/((x2+9)(x-3))

Im not sure how to turn this into a partial fraction.. help.

Thanks

The general form for the PF decomposition would be:

\frac { 18 }{ (x^{ 2 }+9)(x-3) } =\frac { Ax+B }{ x^{ 2 }+9 } +\frac { C }{ x-3 }

First find C by using the Heaviside coverup rule (put x = 3 after multiplying both sides by (x-3).

Then just subtract the \frac { C }{ x-3 } from the LHS and simplify to find the remaining term.
 
Curious3141 said:
The general form for the PF decomposition would be:

\frac { 18 }{ (x^{ 2 }+9)(x-3) } =\frac { Ax+B }{ x^{ 2 }+9 } +\frac { C }{ x-3 }

First find C by using the Heaviside coverup rule (put x = 3 after multiplying both sides by (x-3).

Then just subtract the \frac { C }{ x-3 } from the LHS and simplify to find the remaining term.

ok yeah I figured it out thanks.
 

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