Partial Pressures of an Ideal Gas Mixture Containing Water Vapor

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SUMMARY

The discussion focuses on calculating the partial pressures of a gas mixture containing ammonia (NH3), nitrogen (N2), and water vapor (H2O) at a total pressure of 830 mm Hg and a temperature of 323 K. The mole fractions were correctly calculated as 0.0912 for NH3, 0.891 for N2, and 0.0175 for H2O. The confusion arose regarding the treatment of water vapor, as it behaves like an ideal gas only under certain pressure conditions. The saturation pressure of water vapor at 323 K is 92.5 mm Hg, indicating that the calculated partial pressure of water vapor (14.56 mm Hg) is not saturated, allowing it to be treated as an ideal gas in this context.

PREREQUISITES
  • Understanding of ideal gas laws and equations (PV = nRT)
  • Knowledge of mole fraction calculations (Xi = ni/ntotal)
  • Familiarity with saturation and vapor pressures of water
  • Basic principles of gas mixtures and Dalton's Law of Partial Pressures
NEXT STEPS
  • Research the limitations of the ideal gas approximation for water vapor at varying pressures
  • Study Dalton's Law of Partial Pressures in more detail
  • Explore the concept of saturation pressure and its implications in gas mixtures
  • Learn about the behavior of gases in non-ideal conditions and when to apply corrections
USEFUL FOR

Students in engineering disciplines, particularly those studying thermodynamics or biothermodynamics, as well as professionals dealing with gas mixtures and vapor pressures in practical applications.

kilgorethecat
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Homework Statement



A gas mixture of 0.13 mol NH3, 1.27 mol N2, and 0.025 mol H2O vapor is contained at a total pressure of 830 mm Hg and 323 K. Calculate the following:
(a) Mole fraction of each component.
(b) Partial pressure of each component in mm Hg.
(c) Total volume of mixture in m3 and ft3.

Homework Equations



Xi = ni/ntotal
Ptotal = P1 + P2 + P3 ... + Pn
Pi = XiPtotal
PV = nRT
perhaps others...

The Attempt at a Solution



OK, so I have been working on this for a while now and can't seem to find the answer. Since water vapor only behaves like an ideal gas at pressures below 75 mm Hg, it cannot be treated as so in this problem.

I calculated the mole fractions no problem:
(0.13 mol NH3)/1.425 mol total = 0.0912
(1.27 mol N2)/1.425 mol total = 0.891
(0.025 mol H2O)/1.425 mol total = 0.0175

The problem comes when I try to calculate partial pressures of each gas and the water vapor. Since vapor pressure is a function of temperature alone, I was able to reference a table of values which says at 323 K (50 C), water vapor has a saturation pressure of 92.5 mm Hg. Subtracting this from 830 mm Hg gives 737.5 mm Hg, which should be the remaining combined pressures of ammonia and nitrogen gas. Next, I multiplied each gas's mole fraction by 737.5 mm Hg to obtain their partial pressures. However, according to the ideal gas law, these partial pressures should add up to the total pressure in the container, but they don't.

Can someone please help me understand how to approach and complete this problem? Thank you so much!
 
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Why do you assume water vapor is saturated?
 
V=ntot*R*T/Ptot

Pi=niR*T/V

Am I missing something?
 
RTW69 said:
V=ntot*R*T/Ptot

Pi=niR*T/V

Am I missing something?

No need to calculate volume - molar fractions are enough.
 
I'm sorry, I didn't mean saturation pressure. I meant vapor pressure. So, should I recalculate mole fractions of the two ideal gases excluding water vapor and use that to calculate their partial pressures?
 
kilgorethecat said:
I'm sorry, I didn't mean saturation pressure.

I am afraid you meant it - you have read saturated vapor pressure from the tables and used it in calculations. This is equivalent to assume water vapor was saturated.

I meant vapor pressure. So, should I recalculate mole fractions of the two ideal gases excluding water vapor and use that to calculate their partial pressures?

Use all gases in exactly the same way - that is, ignore water vapor pressure tables. THEN, after you know partial pressure of water, check if it is saturated - IF it is, you have to check how much water would condense and become a liquid. If not, water vapor behaves exactly as every other gas.
 
Doesn't NH3 dissolve rapidly in water to give NH4OH? Can we really consider these components (phases?) as not reacting with each other?
 
Borek said:
I am afraid you meant it - you have read saturated vapor pressure from the tables and used it in calculations. This is equivalent to assume water vapor was saturated.

Crap, you're right! Sorry, my brain gets jumbled from the numbers flying around in my head all day with these engineering classes... and I didn't do so great in psychrometrics or thermodynamics. But I'm in biothermodynamics now, so I need to understand this or it's fail for me.


Borek said:
Use all gases in exactly the same way - that is, ignore water vapor pressure tables. THEN, after you know partial pressure of water, check if it is saturated - IF it is, you have to check how much water would condense and become a liquid. If not, water vapor behaves exactly as every other gas.

So, I calculated the partial pressure of water vapor from the original mole fraction, and I got 14.56 mm Hg. The saturation pressure of water at 50 C from the table is 92.5 mm Hg. Since the value I calculated is less than the value of saturation pressure at that temperature, this means that it is NOT saturated, correct? In that case, if it behaves like an ideal gas, why does almost every source I come across say that the pressure conditions must be below 75 mm Hg? This is the part that confused me in the first place, because I didn't think my given conditions allowed water vapor to behave as the other gases...

On a side note, this is a 300 level class in Biosystems Engineering and I didn't think they would give us that simple of a problem.
 
rude man said:
Doesn't NH3 dissolve rapidly in water to give NH4OH? Can we really consider these components (phases?) as not reacting with each other?

You don't have a liquid water here. No idea if they react in gaseous phase - but I strongly doubt.
 
  • #10
kilgorethecat said:
So, I calculated the partial pressure of water vapor from the original mole fraction, and I got 14.56 mm Hg.

Looks OK to me.

The saturation pressure of water at 50 C from the table is 92.5 mm Hg. Since the value I calculated is less than the value of saturation pressure at that temperature, this means that it is NOT saturated, correct?

Yes.

In that case, if it behaves like an ideal gas, why does almost every source I come across say that the pressure conditions must be below 75 mm Hg?

Must be below 75 mmHg for what?
 
  • #11
Borek said:
Must be below 75 mmHg for what?

From my original post:

kilgorethecat said:
Since water vapor only behaves like an ideal gas at pressures below 75 mm Hg, it cannot be treated as so in this problem.

In my last post when I said I didn't understand how I could treat water vapor as an ideal gas, I was referring to the total pressure (given) of 830 mm Hg. Perhaps to be more clear: I am confused as to whether or not this rule is referring to the TOTAL pressure of a gaseous mixture or the partial pressure of the water vapor itself.

I cannot seem to find a better explanation from a reputable source in my text nor on the web...Either we still don't understand water's role in gaseous mixtures or I am a moron.

Also, thank you SO MUCH for your help so far.
 
  • #12
OK, I see what it is about - whether ideal gas approximation is correct, or not.

To be honest with you I don't know what are limitations. A lot depends on the required accuracy. However, I don't think we have much better approximation, especially for the random mixtures of gases. I seem to remember seeing elaborate tables for some gas mixtures - note that they contain experimental data, not calculated

You can try to ask about ideal gas approximation limitations in the Engineering forum - link to this thread so that people there can check what we have already discussed here.
 
  • #13
borek said:
you don't have a liquid water here. No idea if they react in gaseous phase - but i strongly doubt.

10-4.
 
  • #14
rude man said:
10-4.

Makes 6, but I fail to see your point.
 
  • #15
That's 'Highway Patrol' talk for "OK, understood". This miserable TV show was popular back around 50-60 yrs ago.
 
  • #16
Ah, OK.
 
  • #17
Dang, I was hoping to come to a solid conclusion on this one today since it's due, but you know, I do appreciate your help and will certainly repost for curiosity's sake. You'll hear from me again, thanks again!
 

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