ChemE: vapor pressure and condensation

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SUMMARY

The discussion focuses on calculating the condensation temperature of carbon tetrachloride (CCl4) in a gaseous mixture with dry air at a constant pressure of 1141 mmHg. The initial conditions are 0.190 mol fraction of CCl4 and 0.810 mol fraction of dry air at 62.0°C. To determine the temperature at which 56.0% of CCl4 condenses, participants emphasize the need to calculate the moles of CCl4 that condense and the resulting changes in the gas phase composition, ultimately leading to the determination of the equilibrium temperature based on the partial pressure of CCl4.

PREREQUISITES
  • Understanding of vapor pressure equations, specifically log10(p*) = A + (B/(T+C))
  • Knowledge of mole fractions in gas mixtures
  • Familiarity with concepts of phase equilibrium and condensation
  • Basic thermodynamic principles related to temperature and pressure
NEXT STEPS
  • Study the calculation of partial pressures in gas mixtures
  • Learn about phase diagrams and their application to vapor-liquid equilibrium
  • Explore the Clausius-Clapeyron equation for phase change analysis
  • Investigate the properties of carbon tetrachloride, including its saturation pressure at various temperatures
USEFUL FOR

Chemical engineers, thermodynamics students, and professionals involved in process design and optimization in chemical manufacturing will benefit from this discussion.

GreatEscapist
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Homework Statement


A gaseous mixture containing 0.190 mol fraction of carbon tetrachloride (CCl4) and 0.810 mol fraction of dry air is initially at 62.0°C and 1141 mmHg. If this mixture is cooled at a constant pressure, at what temperature does the CCl4 first start to condense? I already did this problem

At what temperature would 56.0% of the CCl4 condense?

Homework Equations


Partial pressure = p*(T)
log10(p*)= A + (B/(T+C))
I'm sure there are more I'm supposed to use

The Attempt at a Solution



After solving for the original problem, for the second, I know that I need to find how many moles are condensed...but I don't know how to do that. Or what to do after that, or with that information.
 
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Not sure how the dry air enters the problem, but disregarding that, once the CCl4 starts to condense, it is impossible to further reduce the temperature of the (two) CCl4 phases at constant pressure until the CCl4 is saturated liquid. That should answer your question ...
 
GreatEscapist said:

Homework Statement


A gaseous mixture containing 0.190 mol fraction of carbon tetrachloride (CCl4) and 0.810 mol fraction of dry air is initially at 62.0°C and 1141 mmHg. If this mixture is cooled at a constant pressure, at what temperature does the CCl4 first start to condense? I already did this problem

At what temperature would 56.0% of the CCl4 condense?

Homework Equations


Partial pressure = p*(T)
log10(p*)= A + (B/(T+C))
I'm sure there are more I'm supposed to use

The Attempt at a Solution



After solving for the original problem, for the second, I know that I need to find how many moles are condensed...but I don't know how to do that. Or what to do after that, or with that information.

Take as a basis one mole of gas. Then the number of moles of CCl4 is 0.19, and the number of moles of air is 0.81. If 56% of the CCl4 condenses, how many moles of CCl4 liquid is formed, and how many moles of CCl4 remain in the gas phase? What is the total number of moles remaining in the gas phase (air plus CCl4)? At that point, what is the mole fraction of CCl4 in the gas phase? Since the total pressure remains 1141 mm Hg, what is the partial pressure of CCl4 in the gas phase? What is the equilibrium temperature at this vapor pressure of CCl4?
 

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