Particle in a Box: Find Potential Energy U of x

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SUMMARY

The discussion focuses on determining the potential energy U of a particle in a box with a wave function given by Ψ(x) = Axe^{-x^2/L^2} and zero total energy. Participants clarify that zero total energy implies potential energy (PE) equals negative kinetic energy (KE), leading to the equation \(\frac{d^2\Psi}{dx^2} = -\frac{2mU}{\hbar^2} \Psi\). The solution involves applying boundary conditions to derive U as a function of x. Additionally, there is a request for guidance on preparing a lab report on the Hall Effect, indicating a practical application of the discussed concepts.

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  • Understanding of wave functions in quantum mechanics
  • Familiarity with the time-independent Schrödinger equation
  • Knowledge of kinetic and potential energy relationships in quantum systems
  • Basic principles of the Hall Effect and its experimental setup
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  • Study the time-independent Schrödinger equation in depth
  • Learn about boundary conditions in quantum mechanics
  • Explore the derivation of potential energy functions from wave functions
  • Research best practices for writing lab reports, specifically on the Hall Effect
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Students and educators in physics, particularly those studying quantum mechanics and the Hall Effect, as well as anyone involved in experimental physics and lab report writing.

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Homework Statement



In a region of space, a particle with zero total energy has a wave function
\Psi (x) = Axe^{-x^2/L^2}

Find the potential energy U as a function of x.

The Attempt at a Solution



I don't understand how this particle can have zero total energy? Wouldn't this imply that the potential energy is simple 0 everywhere...
 
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Wait, would I have to describe the potential like we do for an infinite square well?
 
Use time-independent Schrödinger eqn.

Zero total energy means that PE=-KE.
 
So with E = 0 I can say \frac{d^2\Psi}{dx^2} = -\frac{2mU}{\hbar ^2} \Psi

which mean I can get solutions just like in my text but I don't what I can apply as boundary conditions or how to get U in terms in x.
 
Last edited:
Divide both sides by psi(x) to get U(x).

psi(x) already obeys the relevant boundary conditions.
 
Ah I see now :P I feel kind of stupid :\

Thanks!
 
thanks!
 
i would lke to b informed how to prepare a lab report on the Hall Effect hopping that i will b given an intensive help over the matter
N.B...i did the experment of the hall effect when a moving conducter moves through a magnetic fild while two variable resistors of 8 and 16 ohms connected to it and the source and the ammeters so as to had the observation
hopping that i will b directed sufficently
urs faithfully......
 

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