- #1
Felicity
- 27
- 0
Homework Statement
a particle is in the ground state of a box with sides x = + or - a. Very suddenly the sides of the box are moved to x = + or - b (b>a). What is the probability the particle will be found in the ground state for the new potential? What is the probability that the particle will be found in the first excited state? In the latter case, the simple answer has a simple explanation. What is it?
2. Homework Equations and the attempt at a solution
I believe the probability can be calculated by An2 where
An = ∫dxψ(x)(2/a)1/2cos(πx/a) for the ground state
An = ∫dxψ(x)(2/a)1/2sin(2πx/a) for the first excited state
Is this correct?
Would the interval be the original or the new walls?
How can I solve this without knowing ψ(x)?
Thank you