Particle motion described by a time dependent function x(t)

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SUMMARY

The particle's position along the x-axis is defined by the function x(t) = 2.00 t³ - 5.00 t + 1.00 m. At t = 4.00 s, the calculated position is 109 m. To determine the velocity and acceleration, apply the definitions of velocity (v = dx/dt) and acceleration (a = dv/dt). The derivatives of the position function will yield the required values for velocity and acceleration.

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elizabethR
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how would i do this...
A particle moving along the x-axis has its position described by the function x=( 2.00 t^{3}- 5.00 t+ 1.00 )\; {\rm m}, where t is in s. At t= 4.00 , what are the particle's position- i calculated that to be 109m , velocity, and acceleration?

i have tried for over an hour on this one problem. i am clueless. my physics book sucks!
 
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Show some work, so we can point out what's wrong.

Btw, for the position at t=4, you already have the x(t) (position function), for velocity and acceleration, look up the definitions.

[tex]v = \dot{x}[/tex]

[tex]a = \dot{v} = \ddot{x}[/tex]
 

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