Particle Motion: Retardation & Arithmetic Progression

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Cbray
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Homework Statement


A particle moves in a straight line away from a fixed point O in the line, such that when its distance from O is x its speed v is given by v=k/x , for some constant k.

(a) show that the particle has a retardation which is inversely proportional to x3
The answer is -k2*x-3

(b) if a,b,c,d are points in that order on the straight line, such that the distances ab, bc, cd are all equal, show that the times taken to travel these successive distances increase in arithmetic progression.

Homework Equations


Possible the answer to the first one comes into relevance, -k2*x-3


The Attempt at a Solution


let the four points have x coordinates
x, x+xo , x+2xo , x+3xo
 
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For part a) how would you find the retardation ? (negative acceleration)

(Hint: use the chain rule to express 'a' in terms of 'v' and 'x')

For part b) try finding time based on t= distance/velocity at the given points.
 
rock.freak667 said:
For part a) how would you find the retardation ? (negative acceleration)

(Hint: use the chain rule to express 'a' in terms of 'v' and 'x')

For part b) try finding time based on t= distance/velocity at the given points.

I still can't figure it out :L
 
Cbray said:
I still can't figure it out :L

If a=dv/dt, can you use the chain rule to re-write this in terms of v and x? (Hint: you will have to have a dv/dx term)