[SOLVED] Particle Position from a V(m/s) vs T(s) Graph A particle starts from Xo=10 m and To=0 and moves with the velocity graph shown in Figure Ex2.11. a. What is the object's position at T=2s, 3s, and 4s? b. Does this particle have a turning point? If so, at what time? I've gotten the answer to b. part. The particle turns at T=3s when the velocity is =0. A. part is giving me problems. I've got the answer to t=2s by figuring the problem like this, the particle starts at 10m when Xo=0 and To=0. So, 10m + 1(8)+2(4)=26m. But, when T=3s and when T=4s, my answers are wrong. The answers in the back of the book give for a. part: When T=3s is 28m, and when T=4s is 26 m. I've attached the questions and the graph, where am I going wrong? Thanks for any help received!