Particle potential energy - acceleration?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
6 replies · 2K views
reminiscent
Messages
131
Reaction score
2

Homework Statement


UCwHlZo.png


Homework Equations


ΔU = Uf - Ui

The Attempt at a Solution


Would I have to make the left side of the equation equal to m*a*x? Is the x on the left side equal to -100 m?
 
Physics news on Phys.org
gneill said:
What's the formal relationship between force and potential energy?
The derivative of potential energy equals force (Fx = -dU/dx). So the derivative would turn it to be: -C/(x2). Then it's just plugging in from there, correct?
 
gneill said:
What's the formal relationship between force and potential energy?
For the acceleration, I got -0.0011 m/s^2. Does that seem too small?
 
reminiscent said:
For the acceleration, I got -0.0011 m/s^2. Does that seem too small?
The magnitude looks good but its sign is suspect. Check the details of your derivative.
 
gneill said:
The magnitude looks good but its sign is suspect. Check the details of your derivative.
Why isn't it negative, though? Since Fx = -dU/dx, wouldn't it be Fx = -(-C*-1*x-2)? It will still be negative.
 
reminiscent said:
Why isn't it negative, though? Since Fx = -dU/dx, wouldn't it be Fx = -(-C*-1*x-2)? It will still be negative.
Oops. You're quite right. My mistake. o:)