Particle's Velocity at x_max: F_0, m, v_0, c

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SUMMARY

The discussion centers on calculating the velocity of a particle with mass m as it reaches its maximum position x_max, under the influence of a variable force F_x = F_0 sin(cx). The initial conditions are set with x_0 = 0 m and an initial velocity v_0 > 0 m/s. The proposed solution involves integrating the force over the displacement and suggests that the final velocity expression should incorporate both the initial velocity and the effects of the force applied over the distance to x_max.

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Homework Statement



A particle of mass m has initial conditions x_0 = 0 m and v_0 > 0 m/s. The particle experiences the variable force F_x = F_0 sin (cx) as it moves to the right along the x-axis, where F_0 and c are constants.

What is the particle's velocity as it reaches x_max? Give your answer in terms of m, v_0, F_0, and c.

Homework Equations



None.

The Attempt at a Solution



Divide force by m and integrate? V_0 - (F_0 * c) / m ?
 
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You got the idea, but shouldn't the final answer depend on x_max as well?
[tex]\int_0^{x_0} \frac{F_0}{m} \sin(c x) = \frac{F_0}{m} \left. -cos(c x)/c \right|_{x = 0}^{x_0} = \frac{F_0}{m c} \left( 1 - \cos(c x_\text{max} \right)[/tex]
plus v_0, or something like that (check the integration, jotted it down)
 

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