Partition function of a classical spring

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SUMMARY

The partition function of a classical spring is determined by its energy, which is given by the formula (1/2)kx^2 when the spring is under constant tension and not oscillating. The confusion arises from mixing concepts of springs and oscillators, where the kinetic energy term (1/2)mv^2 is zero in this static case. Thermodynamically, the force exerted by the spring is linearly proportional to its elongation x, consistent with Hooke's Law.

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Hello. I come across a problem: how to calculate the partition function of a classical spring whose energy is 1/2kx^2, and use thermodynamics to show that the force on the spring is linearly proportional to its elongation x?

I got stuck at the first step. What is the energy of the spring, is it (1/2)kx^2 or (1/2)(p^2/2)+(1/2)kx^2?

Really confused. Thanks in advance for answering the question!
 
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I believe you're becoming confused between a spring and an oscillator. Although the question is vague, I don't think that the spring (and hence any mass attatched to it) is actually moving - this makes the (1/2)mv^2 term equal to zero.

So for a spring under a constant tension (i.e. no oscillation) will have energy (1/2)kx^2.

Hope this helps.
 

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