Partition Function: Understanding Z in Statistical Physics

Click For Summary
The partition function Z in statistical physics serves as the denominator for calculating the probability of a system's state, represented by the formula Z=\sum e^{-E/kT}. It encapsulates the sum of probabilities for all possible states, making it essential for understanding a system's behavior. By analyzing how Z changes with temperature, one can derive various thermodynamic properties of the system. This function effectively consolidates critical thermodynamic features into a single, manageable expression. Understanding Z is key to grasping the qualitative aspects of statistical mechanics.
greenfly
Messages
2
Reaction score
0
In my statistical physics class the partition function Z is used in the calculation of probabilities, and I even have a formula for it: Z=\sume-E/kT. While this is all very good I am having some trouble actually grasping what it is, qualitatively speaking. Would someone please be able to explain it to me? I've tried google-ing, and firstly it pointed me to this site, but I've also followed a couple of other links that don't make much sense to me...

Cheers.
 
Physics news on Phys.org
I'm afraid there's no simple answer to your question. As you will have seen, the partition function is just the denominator when you calculate the probability of observing a particular state; in other words, it's the sum of the probabilities of any state the system could possibly be in. The reason it's useful is that, if we know this sum, and in particular how it changes with temperature, we can actually deduce rather a lot about the system, and calculate any thermodynamic property we please—so it's a way of neatly rolling up a the crucial features of a system's thermodynamics into a single function.

Not sure how useful this will be to you but hope it helps!
 
Thank you! :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K