Passive Transport Homework: Solving Diffusion Problems

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superwolf
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Homework Statement



6enomg.jpg


2. The attempt at a solution

a) The particle seems to be 50 nm in diameter, so

[tex] D = \frac{k_BT}{6 \pi \eta R} = 4.4E-12 m^2s^{-1}[/tex]

b)

[tex] j_{diff}=-D\frac{dc}{dx} = -4.4E-12 \cdot \frac{dc}{dx}[/tex]

I don't know what to do next...Can I assume [tex]c(x) = c_0x[/tex]? In that case,

[tex] j_{diff} = -4.4E-12 c_0[/tex]

Is this correct? What are the units?

And how to do c)?
 
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superwolf said:
I don't know what to do next...Can I assume [tex]c(x) = c_0x[/tex]?

What does the continuity equation tell you about the flux in the tube? Hint: Fick's Second Law