Path ordered integral over simplices?

  • Context: Graduate 
  • Thread starter Thread starter ianhoolihan
  • Start date Start date
  • Tags Tags
    Integral Path
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
ianhoolihan
Messages
144
Reaction score
0
Hi all,

I am trying to follow the derivation by Carroll of the parallel propagator in http://preposterousuniverse.com/grnotes/grnotes-three.pdf notes, beginning page 66 or so.

My question is with the integral in equation 3.40.

1) why is it that this is an integral over a simplice, and not an n-cube (which the limits of integration seem to suggest)?

2) why is it that [itex]\eta_n \geq \eta_{n-1}\geq \ldots \geq \eta_1[/itex] so that path ordering must take place? (See between equations 3.40 and 3.41 for discussion.)

Cheers,

Ianhoolihan
 
Physics news on Phys.org
Hey ianhoolihan.

I can't answer your question specifically, but one thing that you may want to think about is the actual final map that your products of your individual A maps would do to your integral for each simplex.

My guess is that the orientation would be screwed up completely for one and this would affect the integral in a bad way and not give the right result.

Just out of curiosity, what does your linear map A represent?
 
chiro said:
I can't answer your question specifically, but one thing that you may want to think about is the actual final map that your products of your individual A maps would do to your integral for each simplex.

My guess is that the orientation would be screwed up completely for one and this would affect the integral in a bad way and not give the right result.

Just out of curiosity, what does your linear map A represent?

Hmmm, the A maps are (I'm guessing here) an infinitesimal "parallel propagation" in the direction tangent to the curve [itex]\gamma[/itex]. As for the product of the maps, I'm not sure.

I wonder if the reason for [itex]\eta_n \geq \eta_{n-1}\geq \ldots \geq \eta_1[/itex] is to do with the iteration process...actually, I think that might be it. For those not looking at the pdf, the solution for the parallel propagator is

[tex]{P^\mu}_\rho (\lambda,\lambda_0) = {\delta^\mu}_\rho + \int^\lambda_{\lambda_0} {A^\mu}_\sigma(\eta) {P^\sigma}_\rho(\eta,\lambda_0) d\eta[/tex]

So solving by iteration,

[tex]{P^\mu}_\rho (\lambda,\lambda_0) = {\delta^\mu}_\rho +\int^\lambda_{\lambda_0} {A^\mu}_\rho(\eta)d \eta+ \int^\lambda_{\lambda_0} \int^\eta_{\lambda_0} {A^\mu}_\sigma(\eta){A^\sigma}_\rho(\eta')d\eta d\eta' + \ldots[/tex]

The point being that, in the first equation it is [itex]{P^\sigma}_\rho(\eta,\lambda_0)[/itex], so the next substitution must only range from [itex]\eta[/itex] to [itex]\lambda_0[/itex], if you understand the abuse of language.

Yup, I think that works.

Now, for the simplices...oh, maybe it follows from [itex]\eta_n \geq \eta_{n-1}\geq \ldots \geq \eta_1[/itex] quite obviously. For example, in the second term, the integral is over both [itex]\eta,\eta'[/itex] such that [itex]\eta' \leq \eta[/itex]. Hence, simplices.

Thank you.