PC Cell Efficiency: Find Power (in W)

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SUMMARY

The discussion focuses on calculating the power output of a photovoltaic cell with an area of 80 sq cm and an efficiency of 7%. Given the sun's intensity of 800 W/sq m, the correct calculation for power production involves converting the area from square centimeters to square meters. The accurate power output is determined to be 0.448 W, aligning with the conversion of units and efficiency applied in the formula: Power = (intensity) x (area) x (efficiency).

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  • Understanding of photovoltaic cell efficiency
  • Knowledge of unit conversion from square centimeters to square meters
  • Familiarity with power calculations in physics
  • Basic grasp of solar intensity measurements
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rosie_burk
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Homework Statement


A photovoltaic cell has area 80 sq cm and efficiency converting energy in the form of sunlight to electricity of 7%. The sun's intensity is 800 W / sq m and the rays are perpendicular to the cell's surface.
What power will be produced by this cell (in W)? Take care in converting to SI units.


Homework Equations



=(intensity)(area)

The Attempt at a Solution


80*10^-2 *.07 * 800 = 44.8

but the back of the books says the answer is .45
 
Physics news on Phys.org
1 cm = 10-2 m

(1 cm)2 = (10-2 m)2 = ?

Cheers.
 

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