PDE: Wave equation with first order derivative

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SUMMARY

The discussion focuses on solving the wave equation utt = uxx + aux using separation of variables. The boundary conditions are u(0,t) = u(1,t) = 0, with initial conditions u(x,0) = f(x) and ut = g(x). The user attempts a solution by setting U = XT but encounters complications leading to a second-order linear ordinary differential equation (ODE) with constant coefficients for X(x). The discussion highlights the challenges in simplifying the equation and the expectation of a complex solution.

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talolard
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Homework Statement



Solve using separation of variables utt = uxx+aux
u(0,t)=u(1,t)=0
u(x,0)=f(x)
ut=g(x)



The Attempt at a Solution


if not for the ux I'd set
U=XT
such that X''T=TX'' and using initial conditions get a solution.

In my case I get T''X=T(aX'+X'') which is still solvable but highly unpleasant. The question comes from an old exam and I wonder if their is something I'm not seeing?

Thanks!
 
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Consider the substitution u(x,t) = e^{\beta x}v(x,t), for a suitable value of \beta.

EDIT: Forget that, it doesn't simplify as I thought it would. But if you separate the variables as is, you end up with a perfectly normal 2nd order linear ODE with constant coefficients for X(x).
 
Last edited:
talolard said:
In my case I get T''X=T(aX'+X'') which is still solvable but highly unpleasant.
Is it stated anywhere that the solution will be pleasant?
Post your subsequent working down to the point where you find it suspiciously messy.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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