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- Thread starter mjohnston2
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Delphi51

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Since F = ma, a = F*1/m.

Comparing that with good old y = mx + b, the slope on the a vs 1/m graph should be F.

I trust you used the same force for all the data points. The force you used is your "accepted value" for the slope.

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Since F = ma, a = F*1/m.

Comparing that with good old y = mx + b, the slope on the a vs 1/m graph should be F.

I trust you used the same force for all the data points. The force you used is your "accepted value" for the slope.

YES ! i totally understand :) my slope is in Newtons so it would turn out to be F ! Thank you !

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