Periodicity of Inverse Trigonometric Functions

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Homework Help Overview

The discussion revolves around understanding the periodicity of inverse trigonometric functions, specifically how to find recurring values for trigonometric functions and the associated equations for given values.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to derive equations for trigonometric values and seeks clarification on the process of finding all solutions. Participants explore the relationship between angle measures and their cosine values, discussing the periodic nature of the cosine function.

Discussion Status

Some participants have provided insights into the periodicity of the cosine function, suggesting that there are multiple angles corresponding to a single cosine value. The original poster expresses a sense of clarity and understanding following the discussion, indicating a productive exchange of ideas.

Contextual Notes

The original poster references specific equations from their textbook but notes a lack of detail on how to apply them, highlighting a potential gap in understanding the underlying concepts.

Liger20
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Homework Statement



My problem from before has been more or less resolved, but now I have a new, bigger problem. I need to figure out how to find recuring values for trig functions. I'm having a hard time figuring out how to

1. Get the equations associated with a given value for the trig functions
2. Actually finding all of those values.

This is a problem for me because I can tell that this is a critical concept.


Homework Equations



My book gives me these equations for radians: x=30+360n or x=150+360n
For radians: pi/6+2piN or 5pi/6+2piN. The book goes into little detail as to how to work these equations, and I would very much appreciate it if someone could tell me how to work them.



The Attempt at a Solution



One problem reads: List the solutions in degrees: cos^-1(1/2)= 60 (degrees), 300, 420, 660, 780, 1020, and I have absolutely no idea how they came up with that answer. Like I said before, I would really appreciate it if someone could help me with this, and please tell me if I should clarify any part of what I'm asking.
 
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Think about it the other way around: What are all the angle measures (in degrees) for which the cosine of that angle is 1/2?

There are going to be two angles in each 360 degree full circle, so (in degrees),
.5 = cos(60) = cos(300) = cos(360 + 60) = cos(360 + 300) = cos(720 + 60) = cos(720 + 300) = ...

All of the cosine function arguments are of the form 60 + n*360 or 300 + n*360, where n is an integer. (I have shown them for nonnegative integers n, but the pattern applies also to negative integers.
 
Whoa, that just clicked beautifully. THANK YOU! I'm pretty sure I understand what I'm doing now.
 
Liger20 said:
Whoa, that just clicked beautifully. THANK YOU! I'm pretty sure I understand what I'm doing now.

You're welcome!
 

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