Permutation and combination question

Click For Summary
SUMMARY

The discussion revolves around calculating the number of ways to position 5 men and 4 women for a photo shoot, with the men fixed in height order. The initial calculations yielded a total of 2154 arrangements, while the correct answer is 3024. Key cases considered include grouping women together or separating them, with specific permutations calculated for each scenario. The discrepancy arises from miscalculations in the grouped arrangements, particularly in the case of women standing together and the total permutations of women.

PREREQUISITES
  • Understanding of permutations and combinations
  • Familiarity with factorial notation (n!)
  • Knowledge of binomial coefficients (nCr)
  • Basic principles of counting arrangements
NEXT STEPS
  • Review the principles of permutations and combinations in combinatorial mathematics
  • Learn about factorial calculations and their applications in counting problems
  • Study binomial coefficients and their role in grouping arrangements
  • Practice similar problems involving arrangements of distinct objects
USEFUL FOR

Students studying combinatorial mathematics, educators teaching permutations and combinations, and anyone interested in solving arrangement problems in mathematics.

gaobo9109
Messages
68
Reaction score
0

Homework Statement


A photographer is positioning 5 men and 4 women for a photo shoot. The men are positioned in the order from shortest on the left to tallest on the right. Find the number of ways the photographer can position them in a row. (All men are of different heights and are not necessarily standing together in a group)

Homework Equations


The Attempt at a Solution


Since the position of men are fixed, i will just consider the possible permutation of women.

Four women can either stand together as one group, or split into two, three or four groups.

Below are combination forl 5 possible cases
Grouped together: 6 x 4! = 360
Form two groups of 2: 4C2/2 x 6P2 = 90
Form two groups of 1 and 3: 4 x 6P2 = 120
Form three groups of 1,1 and 2: 4 x 3 x 6P3 = 1440
All separated: 6P4 = 360

Then I added up all the possible combinations. The answer I obtained is 2154. However, the answer provided is 3024. Can anyone tell me which case I fail to consider? Or is there anything wrong with my working? Thanks
 
Physics news on Phys.org
gaobo9109 said:

Homework Statement


A photographer is positioning 5 men and 4 women for a photo shoot. The men are positioned in the order from shortest on the left to tallest on the right. Find the number of ways the photographer can position them in a row. (All men are of different heights and are not necessarily standing together in a group)


Homework Equations





The Attempt at a Solution


Since the position of men are fixed, i will just consider the possible permutation of women.

Four women can either stand together as one group, or split into two, three or four groups.

Below are combination forl 5 possible cases
Grouped together: 6 x 4! = 360
6x24=144, not 360.
Form two groups of 2: 4C2/2 x 6P2 = 90
I'm too tired to figure out what you're doing, but I got 360 for this case.
Form two groups of 1 and 3: 4 x 6P2 = 120
And 720 for this case.
Form three groups of 1,1 and 2: 4 x 3 x 6P3 = 1440
All separated: 6P4 = 360
We agree on these cases.
Then I added up all the possible combinations. The answer I obtained is 2154. However, the answer provided is 3024. Can anyone tell me which case I fail to consider? Or is there anything wrong with my working? Thanks
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
59
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K