The discussion centers on finding a general formula for the permutation of n objects, where some elements are identical. It suggests using binomial coefficients to calculate the arrangements, focusing on one factor for each set of identical elements. The example provided illustrates that there are (5 choose 3) or (5 choose 2) different permutations for the sequence (1,1,1,2,2). The last factor in the calculation is considered to be 1 and can be disregarded. This method effectively addresses the challenge of counting permutations with identical items.