Permutations and Combinations Problem

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The problem involves determining the number of ways to select one or more letters from the word "INSIPIDITY." The initial approach mistakenly counted combinations with repeated letters, leading to over-counting. A more efficient solution is presented using the formula ((4+1)(1+1)^6) - 1, which accounts for the independent choices of each letter, including the repetitions of "I." The discussion highlights the challenge of finding a systematic approach to permutations and combinations, contrasting it with the more straightforward procedures in calculus. Understanding various methods and practicing them is emphasized as key to mastering this topic.
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Homework Statement


In how many ways is it possible to select one or more letters from those in INSIPIDITY?


Homework Equations





The Attempt at a Solution


My initial impression was that this was a combinations problem and I did not have to take into account the repetitions. This led me to over-count because I had counted combinations like SIPI multiple times as SI2PI3 and SI1PI4 are indistinguishable. The only method I could think of was for each number of selected letters to add up the mutually exclusive scenarios that constituted it, as follows

1 letter selected: no I involved, 1 I involved
2 letters selected: no I's involved, 1 I involved, 2 I's involved
3 letters selected: no I's involved, 1 I involved, 2 I's involved, 3 I's involved etc.

Apparently ((4+1)(1+1)^6) -1 is a much quicker solution, however I am unable to interpret the logic of this solution. Could someone please explain it to me? Also if anyone could offer some tips on how to tackle these problems I would appreciate it, I have found this to be the most difficult subject I have encountered so far, mainly because there doesn't seem to be a procedure to follow like there was for calculus.
 
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You can take (0, 1, 2, 3 or 4) letters "I" -> 4+1 options
You can take (0 or 1) letters "N" -> ...
...
All those choices are independent of each other.

mainly because there doesn't seem to be a procedure to follow like there was for calculus.
There are always many ways to find a solution, the more ways you know and recognize (needs practice!) the easier it is to find a good one.
 
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Thanks for the help.
 

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