- #1
ClosedCastle
- 5
- 0
How can I solve this?
Find the value of n.
1. P(n,2)=90 ; 2. P(n,3)=3P(n,2)
I tried like this but I am stuck
1. n! / (n-2)! = 90 and then I don't know ...
2. n!/(n-3!) = 3 n!/(n-2)! ⇔ n! (n-2)! / (n-3)! n! = 3 ⇔ (n-2)! / (n-3)! = 3 here the same
As you can see I'm really stuck with this.
Find the value of n.
1. P(n,2)=90 ; 2. P(n,3)=3P(n,2)
I tried like this but I am stuck
1. n! / (n-2)! = 90 and then I don't know ...
2. n!/(n-3!) = 3 n!/(n-2)! ⇔ n! (n-2)! / (n-3)! n! = 3 ⇔ (n-2)! / (n-3)! = 3 here the same
As you can see I'm really stuck with this.