- #1

- 343

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*x*objects containing

*a*repeats of one element and

*b*repeats of another, N

_{p}(without repetition)=x!/(a!b!).

If you have

*x*objects and repetitions are allowed, N

_{p}(with repetition)=x

^{x}, correct?

Combining these, if we have

*x*objects containing

*a*repeats of one element and

*b*repeats of another, and repetitions are allowed, N

_{p}(with repetition)=x

^{x}/(a!b!). Is this right?