- #1
Big-Daddy
- 343
- 1
The theory says that if you have x objects containing a repeats of one element and b repeats of another, Np(without repetition)=x!/(a!b!).
If you have x objects and repetitions are allowed, Np(with repetition)=xx, correct?
Combining these, if we have x objects containing a repeats of one element and b repeats of another, and repetitions are allowed, Np(with repetition)=xx/(a!b!). Is this right?
If you have x objects and repetitions are allowed, Np(with repetition)=xx, correct?
Combining these, if we have x objects containing a repeats of one element and b repeats of another, and repetitions are allowed, Np(with repetition)=xx/(a!b!). Is this right?