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Permutations with Repetition and Repeated Elements

  1. May 12, 2013 #1
    The theory says that if you have x objects containing a repeats of one element and b repeats of another, Np(without repetition)=x!/(a!b!).

    If you have x objects and repetitions are allowed, Np(with repetition)=xx, correct?

    Combining these, if we have x objects containing a repeats of one element and b repeats of another, and repetitions are allowed, Np(with repetition)=xx/(a!b!). Is this right?
     
  2. jcsd
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