Perturbed Ground State Wavefunction with Parity

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Homework Help Overview

The discussion revolves around a particle in a Coulomb potential and the effects of a perturbation on its ground state wavefunction. Participants are examining how symmetries of the perturbation, particularly parity, influence the coefficients in the perturbed ground state representation.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the implications of parity on the coefficients C_{nlm} in the context of perturbation theory. There is a focus on how parity might create selection rules and restrict the values of these coefficients. Some participants express confusion about the relationship between the parity operator and the perturbation.

Discussion Status

There is ongoing exploration of the role of parity in the problem, with some participants seeking clarification and guidance on how to apply the concept to the coefficients. Multiple interpretations of the implications of parity are being discussed, but no consensus has been reached.

Contextual Notes

Participants are working under the constraints of a homework assignment, with specific attention to the perturbation's symmetries and their effects on the quantum states involved. There is mention of an exam context, which may influence the urgency and focus of the discussion.

logic smogic
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[SOLVED] Perturbed Ground State Wavefunction with Parity

Homework Statement


A particle is in a Coulomb potential

[tex]H_{0}=\frac{|p|^{2}}{2m} - \frac{e^{2}}{|r|}[/tex]

When a perturbation V (which does not involve spin) is added, the ground state of [itex]H_{0} + V[/itex] may be written

[tex]|\Psi_{0}\rangle = |n=0,l=0,m=0\rangle + \sum C_{nlm}|n,l,m \rangle[/tex]

where [itex]|n,l,m\rangle[/itex] is a Hyrdogenic wavefunction with radial quantum number n and angular momentum quantum numbers l, m.

Consider the following possible symmetries of the perturbation V. What constraints, if any, would the presence of such a symmetry place on the possible values of the coefficients [itex]C_{nlm}[/itex]?

(i) Symmetry under Parity.
(ii) Rotational symmetry about the z axis.
(iii) Full rotational symmetry.
(iv) Time reversal symmetry.

The Attempt at a Solution



Let's stick to just part (i) for now.

Initially, I want to understand what the question is asking, and what that formula for the ground state ket means. Here's what went through my head:

1. Time-Independent perturbation theory tells us that the eigenkets can be written:

[tex]|n \rangle = |n_{0} \rangle + \sum |m_{0} \rangle \langle m_{0} | n \rangle[/tex]

where,

[tex]\langle m_{0} | n \rangle = \lambda \frac{\langle m_{0} | V | n \rangle}{E_{n} - E_{m,0}}[/tex]

2. Comparing this to the equation of the perturbed ground state (in the statement of the problem), it looks like,

[tex]|n=0,l=0,m=0\rangle \rightarrow |n_{0} \rangle[/tex]

and,

[tex]|n,l,m \rangle \rightarrow |m_{0} \rangle[/tex]

which leaves the "coefficients" as,

[tex]C_{nlm} \rightarrow \langle m_{0} | n \rangle[/tex]

3. As for parity, I know that if [itex]\pi[/itex] is the parity operator, then for an operator A,

[tex]\pi^{\dagger} A \pi = \pm A[/tex]

Presumably, I should apply this to V, and learn something about the possible values of the coefficients.

This is where I'm stuck. I've no idea how this is supposed to restrict the values that [itex]C_{nlm}[/itex] can take. Any suggestions or hints in the right direction?
 
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Any thoughts on this? The basic question here is:

How does parity create selection rules?

Perhaps someone could just lay out it for me, or point me to a nice tutorial. My book doesn't provide an example or anything of that sort, and I have an exam today! Thanks much.
 
Something's not kosher here...

So the strangest thing just happened. I just had a Quantum Mechanics exam today. I came home and decided to research a couple of the problems on the exam, and sure enough, on your thread are posted 2 of the EXACT questions that were on my exam. But even stranger than this, is the fact that these posts were made 2 days before my test...I wonder how that happened?? Any suggestions anyone?

-What school did you say that you attended by the way?
 
logic smogic said:

Homework Statement


A particle is in a Coulomb potential

[tex]H_{0}=\frac{|p|^{2}}{2m} - \frac{e^{2}}{|r|}[/tex]

When a perturbation V (which does not involve spin) is added, the ground state of [itex]H_{0} + V[/itex] may be written

[tex]|\Psi_{0}\rangle = |n=0,l=0,m=0\rangle + \sum C_{nlm}|n,l,m \rangle[/tex]

where [itex]|n,l,m\rangle[/itex] is a Hyrdogenic wavefunction with radial quantum number n and angular momentum quantum numbers l, m.

Consider the following possible symmetries of the perturbation V. What constraints, if any, would the presence of such a symmetry place on the possible values of the coefficients [itex]C_{nlm}[/itex]?

(i) Symmetry under Parity.
(ii) Rotational symmetry about the z axis.
(iii) Full rotational symmetry.
(iv) Time reversal symmetry.


The Attempt at a Solution



Let's stick to just part (i) for now.

Initially, I want to understand what the question is asking, and what that formula for the ground state ket means. Here's what went through my head:

1. Time-Independent perturbation theory tells us that the eigenkets can be written:

[tex]|n \rangle = |n_{0} \rangle + \sum |m_{0} \rangle \langle m_{0} | n \rangle[/tex]

where,

[tex]\langle m_{0} | n \rangle = \lambda \frac{\langle m_{0} | V | n \rangle}{E_{n} - E_{m,0}}[/tex]
This is a very bad choice of notation because [tex]\langle m_{0} | n \rangle[/tex] has already a clear meaning. Maybe [tex]V_{m_0,n}[/tex] or something similar would be better.
2. Comparing this to the equation of the perturbed ground state (in the statement of the problem), it looks like,

[tex]|n=0,l=0,m=0\rangle \rightarrow |n_{0} \rangle[/tex]

and,

[tex]|n,l,m \rangle \rightarrow |m_{0} \rangle[/tex]

which leaves the "coefficients" as,

[tex]C_{nlm} \rightarrow \langle m_{0} | n \rangle[/tex]

3. As for parity, I know that if [itex]\pi[/itex] is the parity operator, then for an operator A,

[tex]\pi^{\dagger} A \pi = \pm A[/tex]

Presumably, I should apply this to V, and learn something about the possible values of the coefficients.

This is where I'm stuck. I've no idea how this is supposed to restrict the values that [itex]C_{nlm}[/itex] can take. Any suggestions or hints in the right direction?

V cannot change the parity therefore the two states connected by V must have the same parity. What is the parity of a state with quantum numbers l,m ?
 

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