1. The problem statement, all variables and given/known data You have a 1L of a 2M HCl solution. Assume that the HCl completely ionizes. a) Calculate the pH of the solution right now. b) You now add V litres of water to the solution. Find the pH of the new dilute solution in terms of V. 2. Relevant equations pH = -log[H] 3. The attempt at a solution a) pH = -log(2) which is interestingly a negative number so I hope this is correct. b) I'm not sure how you would do this part. Do we just find the new concentration in terms of V and then find the negative log of that? Don't we have to consider the autoionization of water? Thanks! BiP
Yes, negative pH is possible. Check the link I posted in your other thread for the way pH should be calculated. And read about dilution calculation.