Phase Difference of Transfer Function H(jw)

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Homework Help Overview

The discussion revolves around the phase difference in a transfer function represented as H(jw) = |Vo/Vi|. Participants are exploring how to determine the phase relationship between the output voltage (Vo) and the input voltage (Vi).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the implications of a positive phase angle in relation to the output leading or lagging the input. Some participants provide clarification on the meaning of positive and negative phase differences.

Discussion Status

Participants are actively engaging with the concept of phase difference, with some guidance offered regarding the interpretation of phase angles. There is an ongoing exploration of the definitions and implications of leads and lags in this context.

Contextual Notes

The original poster expresses difficulty in finding clear explanations in texts regarding the relationship between phase angles and the lead/lag behavior of the output relative to the input.

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Homework Statement


If I have a transfer function [tex]H(jw)= |\frac{V_o}{V_i}|[/tex]. I need to find the phase difference between Vo and Vi.


Homework Equations





The Attempt at a Solution


The phase angle is [tex]tan^{-1}(\frac{Im(H)}{Re(H)})[/tex]. My problem is that if I get a positive angle, does this mean that the Output leads or lags the input? I can't find this explained clearly in any text.
 
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A positive phase difference is a lead. A negative phase difference is a lag.
 
nicktacik said:

The Attempt at a Solution


The phase angle is [tex]tan^{-1}(\frac{Im(H)}{Re(H)})[/tex]. My problem is that if I get a positive angle, does this mean that the Output leads or lags the input? I can't find this explained clearly in any text.

Leads.
 
Thanks.
 

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